问题描述

下面的脚本我想实现连续输入3次账号密码错误自动跳转到禁止登陆页面怎么实现

 <script>
   function check(){
      var name=document.getElementById("name").value;
   var pass=document.getElementById("pass").value;
   if(name=="账号" && pass=="密码"){
   alert("登入成功");
   window.document.f.action="shujubiao/";
   window.document.f.submit();

   }else{
   alert("用户名或密码错误");

   }

   }
</script>

解决方案

 var errCount = 0;
function check() {
    if (errCount < 3) {
        var name = document.getElementById("name").value;
        var pass = document.getElementById("pass").value;
        if (name == "账号" && pass == "密码") {
            errCount = 0;
            alert("登入成功");
            window.document.f.action = "shujubiao/";
            window.document.f.submit();
        } else {
            errCount++;
            alert("用户名或密码连续错误次数" + errCount);
        }
    }

    if (errCount == 3) {// 连续输入3次账号密码错误
        location.href = "登陆页地址..";
    }
}

解决方案二：

    function check() {
        var name = document.getElementById("name").value;
        var pass = document.getElementById("pass").value;
        if (name == "账号" && pass == "密码") {
            alert("登入成功");
            window.document.f.action = "shujubiao/";
            window.document.f.submit();

        } else {
            alert("用户名或密码错误");
            count++;
            if (count >= 3) location = 'xxxxxx';

        }

    }