本人在scrapy-redis项目中的setting.py中配置，可时中有问题。但是可以使用以下方法：

首先，你要确保安装了splash，并且已经启动

（1）先安装scrapy-splash库：

[python] view
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1. pip install scrapy-splash  

（2）然后将我们的Docker起起来

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1. docker run -p 8050:8050 scrapinghub/splash
    

在原有scrapy-redis项目基础上，只需要在spider中重写生成request的方法即可。主要原理时是把url转发给splash，让splash解析后返回

（1）普通爬虫中，

注意：如果是scrapy,并且没有使用scrapy-redis可以使用配置的方法，参见 http://blog.csdn.net/u013378306/article/details/54409215

# -*- coding: utf-8 -*-
from scrapy import Request
from scrapy.spiders import Spider
from scrapy.http import Request, HtmlResponse
from scrapy.selector import Selector
import json
class WeiXinSpider(Spider):
    name = 'test'
    start_urls = [
        'https://item.jd.com/2600240.html'
    ]
    global splashurl;
    splashurl = "http://localhost:8050/render.html";# splash 服务器地址

    #此处是重父类方法，并使把url传给splash解析
    def make_requests_from_url(self, url):
        global splashurl;
        url=splashurl+"?url="+url;
        body = json.dumps({"url": url, "wait": 5, 'images': 0, 'allowed_content_types': 'text/html; charset=utf-8'})
        headers = {'Content-Type': 'application/json'}
        return Request(url, body=body,headers=headers,dont_filter=True)

    def parse(self, response):
        print "############"+response._url

        fo = open("jdeeeeeeeeee.html", "wb")
        fo.write(response.body);  # 写入文件
        fo.close();
        '''site = Selector(response)
        links = site.xpath('//a/@href')
        for link in links:
            linkstr=link.extract()
            print "*****"+linkstr
            yield SplashRequest(linkstr, callback=self.parse)'''

（2）scrapy-redis中，和上面相同

#encoding: utf-8
from scrapy.spiders import Rule
from scrapy.linkextractors import LinkExtractor
from scrapy_redis.spiders import RedisCrawlSpider
import json
from scrapy.http import Request, HtmlResponse
class MyCrawler(RedisCrawlSpider):
    """Spider that reads urls from redis queue (myspider:start_urls)."""
    name = 'mycrawler_redis'
    redis_key = 'mycrawler:start_urls'
    #start_urls = ['https://zhidao.baidu.com/question/2205192714330042628.html?fr=iks&word=scrapy&ie=gbk']
    rules = (
        # follow all links
        Rule(LinkExtractor(allow=('/question/.*'),
                               restrict_xpaths=('//a[@class="related-link"]')), callback='parse_page', follow=True),
    )
    global splashurl;
    splashurl = "http://localhost:8050/render.html";
    # splash 服务器地址
    #此处是重父类方法，并使把url传给splash解析
    def make_requests_from_url(self, url):
        global splashurl;
        url = splashurl + "?url=" + url;
        body = json.dumps({"url": url, "wait": 5, 'images': 0, 'allowed_content_types': 'text/html; charset=utf-8'})
        headers = {'Content-Type': 'application/json'}
        return Request(url, body=body, headers=headers, dont_filter=True)

    def __init__(self, *args, **kwargs):
        # Dynamically define the allowed domains list.
        domain = kwargs.pop('domain', '')
        self.allowed_domains = filter(None, domain.split(','))
        super(MyCrawler, self).__init__(*args, **kwargs)

    def parse_page(self, response):
        print "#####"+response._url
        return {
            'name': response.css('title::text').extract_first(),
            'url': response.url,
        }