题目链接:
http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=108&page=show_problem&problem=129
原题:
You are to write a program that tries to find an optimal coloring for a given graph. Colors are applied to the nodes of the graph and the only available colors are black and white. The coloring of the graph is called optimal if a maximum of nodes is black. The coloring is restricted by the rule that no two connected nodes may be black.
Figure: An optimal graph with three black nodes
题目大意:
给一张图染色, 只能染白色或黑色, 不能让相连的两个点都是染成黑色(白色的可以)。 求这张图能染黑色的最多点数
分析与总结:
其实就是对于每一个点,染黑,或者不染黑的问题。直接暴力搜索即可。
参考:王晓东的《计算机算法设计与分析第三版》P163页 ”图的m着色问题“。
代码:
#include<iostream> #include<cstdio> #include<algorithm> #include<cstring> #define MAXN 102 using namespace std; int n,k, G[MAXN][MAXN], maxVal; int color[MAXN], ans[MAXN]; // 判断与这个点相连的是否有黑色的 inline bool isOk(int u){ for(int i=1; i<=n; ++i) if(G[u][i] && color[i])return false; return true; } void search(int u, int num){ if(u > n){ if(num > maxVal){ maxVal = num; memcpy(ans, color, sizeof(ans)) ; } return; } if(num + n - u + 1 <= maxVal) return;// 减枝 if(isOk(u)){ color[u] = 1; search(u+1, num+1); color[u] = 0; } search(u+1, num); } int main(){ #ifdef LOCAL freopen("input.txt","r",stdin); #endif int T, u, v; scanf("%d",&T); while(T--){ scanf("%d %d", &n, &k); memset(G, 0, sizeof(G)); for(int i=0; i<k; ++i){ scanf("%d %d", &u, &v); G[u][v] = G[v][u] = 1; } maxVal = -2147483646; memset(color, 0, sizeof(color)); search(1, 0); printf("%d\n", maxVal); bool flag=true; for(int i=1; i<=n; ++i)if(ans[i]){ if(flag){ printf("%d",i); flag=false;} else printf(" %d",i); } printf("\n"); } return 0; }
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