解密-怎么得到以下原始二进制字符串的真实内容？

问题描述

怎么得到以下原始二进制字符串的真实内容？

请问以下这个原始字符串这个是通过什么编码的呢？我用assii解密后得到后面的assii格式的字符串，但是也是一堆东西，只有9000000360是明文数据

原始字符串：

0060100030303030304e003000000000393030303030303336300000000000000e0707070707070b0e083838383831395f5f080d0904020d3a3a3a3a3333333b3b3b3b343434343c3c3c35353535353d3d36360f0f1806100719020f3737373838383838383831393939393909021f0f0a170f0c1e7207160c0216767234343c
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
000a100130303030304e003000000000393030303030303336300000000000000952030c1d5e5b011b62
0040100530303030304e003000000000393030303030303336300000000000000052030c1d5e5b021c6334614633213a05520c1a5f53021c543562472d223b64353e2f6966332c553663412e233c65363f296a57041d66075d422f243d663739
0000100530303030304e00300000000039303030303030333630000000000000
0040101230303030304e003000000000393030303030303336300000000000000052030c1d5e5b021c6334614633213a05520c1a5f53021c543562472d223b64353e2f6966332c553663412e233c65363f296a57041d66075d422f243d663739
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
002b123330303030304e003000000000393030303030303336300000000000006d307278683c2275176a04517603110a50020d2f3b37736f0462267a4b440a5005081f5e677763127f277c
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
002d124030303030304e003000000000393030303030303336300000000000006d307278683c2275176a04517603110a50020d2f3b37736f0462267a4b440a5005081f5e677763127f277c2f22
00c3124030303030304e00300000000039303030303030333630000000000000602f7c7268376a78641e7b2f036a20753660706121206b2a1267270277677f297a706a30677b6319722f0e7d703d20787e6b26227962187204436a6a7c247b7c653e3c7861197407427d6a702268686e21287f61507c1a137c676d2a776f7a2c26366f1b612d0c762678316079793d38646755055075070f0252350d005f55331b7a0552461d0c0b54340c1850480b18540752721a0d0454370e1859531a1567366c731c10135e0638195f5c1b166330677300150e5701091d5c68071b660b71720420
003b101130303030304e003000000000393030303030303336300000000000000052030c1d5e5b021c6334614633213a05520c1a5f53021c543562472d223b64353e2f6966332c553663412e233c65363f296a56052d56375d422f
0000101130303030304e00300000000039303030303030333630000000000000

ACSII解码后的字符串：

.`..00000N.0....9000000360................888819__.
..
::::333;;;;4444<<<55555==66.........7778888888199999 ...
....r.....vr44<.
..00000N.01...9000000360........V...^] .i ey.9. .. ...........

......
..............
..................................
.4...................7.......8.....................3;

..H... @....I....66...............................Rj.J^. ......
...5..............ny......

........... ::333;;;;4444<<<.
..00000N.0....9000000360...... R...^[..b.@..00000N.0....9000000360.......R...^[..c4aF3!:.R.._S..T5bG-";d5>/if3,U6cA.#/if3,U6cA.#
..D...IF..u.Ca...E.. JG.
v.}b...F..
KH..w.~c...G...LI..q..d...A...MJ. r.@e...B..
NK.
s./.}otC...OE..t.RG
..D...iF..u.Cq...E.. JG.
v.}b...R...KH..w.~c...W.
.LI..q..d...Q...MJ. r.@e...S...NK.
s.Af...C...OE..t.Bg
..D...IF..u.Ca...E...JG.
v.}b...F...kh5.W1^C0%>g1:+li6/Q2_D1&?a2;,mj.+.300000N.0....9000000360......m0rxh<"u.j.Qv..
P.
/;7so.b&zKD
P...^gwc..'|.!.300000N.0....9000000360......n#ayd*jfk.q/.~d;4uok= .j.{c.llh*s.*)x.d*.k"r ao{#$q,.v. jpk'{8b$$qb.b
Bviq&ejn>*sa.3..xrm$bzu#?z(.r).bi#jqb .h+.{3.voo.5{{#)|j.pc.ccy(pnf*-}y.7".}fh6ejdk {b.d.
aadgqko.2p.|_.yws.u<.X..3............(c2QD...S
..oX..}.UG...M. /]R..l.cs...]
?.hV..e7S@......([f..a.st.%.S. .jX4.g.ns..
Q.<.-.@00000N.0....9000000360......m0rxh<"u.j.Qv..
P.
/;7so.b&zKD
P...^gwc..'|/"...@00000N.0....9000000360....../|rh7jxd.{/.j u6pa! k*.g'.wg.)zpj0g{c.r/.}p= x~k&"yb.r.Cjj|${|e><xa.t.B}jp"hhn!(.aP|..|gm*woz,&6o.a-.v&x1yy=8dgU.Pu...R5
._U3.z.RF...T4..PH..T.Rr.
.T7..YS..g6ls...^.8._..c0gs...W. .h..f.qr. .;..00000N.0....9000000360.......R...^[..c4aF3!:.R.._S..T5bG-";d5>/if3,U6cA.#<e6?)jV.-V7]B/....00000N.0....9000000360......

解决方案

有些内容，比如整数、浮点数、日期时间、字节流等等它们是不读的。

时间： 2024-09-15 08:46:56

解密-怎么得到以下原始二进制字符串的真实内容？的相关文章

把普通字符串转换成二进制字符串的函数写出来了，和大家分享一下。

二进制|函数|转换|字符串 '普通字符串转换成二进制字符串函数Function Str2Bin(String)  Dim i, tmpbin  For i=1 to strLength(String)    tmpbin = tmpbin & ChrB(Asc(Mid(String,I,1)))  Next  Str2Bin = tmpbinEnd Function '以下函数来自ChinaASP,计算字符串的真正字节数(支持中文)Function strLength(str)   If (le

支持中文的把普通字符串转成二进制字符串的函数

二进制|函数|中文|字符串 上次的函数有误,这次的才正确支持中文. '把普通字符串转成二进制字符串Function str2bin(varstr)   str2bin=""   For i=1 To Len(varstr)       varchar=mid(varstr,i,1)       varasc = Asc(varchar)       If varasc<0 Then          varasc = varasc + 65535       End If    

c++-C++下int型转换成固定长度二进制字符串

问题描述 C++下int型转换成固定长度二进制字符串 我想把int型的数据转换成32位的01字符串 用itoa函数的话,前面的0好像会被忽略掉,有什么简单的函数可以用? 解决方案 int main() { char str[] = "00000000000000000000000000000000"; int n = 1234; for (int i = 0; i < 32; i++) if (((1 << i) & n) == (1 << i))

统计一个二进制字符串中1的个数的算法

记得在吴军的<数学之美>中有一章讲到布尔代数和搜索引擎的索引.大概是讲通过一个二进制字符串来标识当前关键词在那些文档中出现过.二进制字符串中1的位置就是出现这个词文档的id. 如,一淘 对应一个二进制字符串 1010001.其中在1,5,7三个位置出现了1,说明文档id为1,5,7的文章包含词"一淘".但是在书中没有说如何统计1的个数和位置.现在我补充以下实现算法. 代码如下: #include <iostream> #include <math.h>

char-MATLAB 如何实现 等长 二进制字符串 按位异或？

问题描述 MATLAB 如何实现 等长 二进制字符串 按位异或? 如 A='10110010' :B='11011001' ;两者为字符串,如何实现按位异或,使得C='01101011'.其中结果C也是字符串!曾查得一解法为:C=char(xor(A-8,B-8)+8):但运行结果总是错误!求解析(C=char(xor(A-8,B-8)+8):这用法正确吗???) (因为真正应用时A.B.C三者长度要保持一致,所以不考虑将字符串转成数值类型然后进行的'bitxor'.) MATLAB 菜鸟向 各

如何将二进制字符串转换为byte[]?

问题描述 byte[] b = new byte[fis.available()];StringBuilder str = new StringBuilder();fis.read(b);for(byte bs:b){ str.append(Integer.toBinaryString(bs));//转换为二进制 }fis.close();我通过这种方式将一个byte[]转换为二进制的字符串.里面全是0和1字符.现怎么将这种二进制字符串转换为byte[]数组?我知道有其它将byte[]和字符串之

c#中如何把一个96个字节的二进制字符串转换成12个字节的十六进制数

问题描述 c#中如何把一个96个字节的二进制字符串转换成12个字节的十六进制数 c#中如何把一个96个字节的二进制字符串转换成12个字节的十六进制数? 解决方案 96个字节超过了64位长度,你需要拆成两个再组合 Convert.ToInt64("1001101", 2).ToString("X") 解决方案二: 可以参考一下:http://blog.csdn.net/lijiancheng0614/article/details/45130893 里面有讲前面补0的

PHP实现将科学计数法转换为原始数字字符串的方法_php技巧

本文实例讲述了PHP实现将科学计数法转换为原始数字字符串的方法,分享给大家供大家参考. 具体实现代码如下: 复制代码 代码如下: function NumToStr($num){     if (stripos($num,'e')===false) return $num;     $num = trim(preg_replace('/[=\'"]/','',$num,1),'"');//出现科学计数法,还原成字符串     $result = "";     wh

C#中如何把二进制字符串转化为二进制

问题描述 比如把字符串"1001101"转化为二进制数1001101返回 解决方案 解决方案二:strings="1001101";byteb=Convert.ToByte(s,2);解决方案三:usingSystem;publicclassByteConversion{publicstaticvoidMain(){stringbyteString=null;CallTryParse(byteString);byteString=String.Empty;CallT