问题描述
for循环能用吗?
解决方案
public static void main(String[] args) {TestClass tc = new TestClass();System.out.println("需要的圣诞树的大小:");Scanner input = new Scanner(System.in);int a = input.nextInt();tc.Tree(2 * a);}public void Tree(int n) {int i, j, k, m;for (i = 1; i <= n / 2; i++) {for (j = 1; j < n / 2 + i; j++) {if (j <= n / 2 - i)System.out.print(" ");else {if (j % 2 == 0)System.out.print("*");elseSystem.out.print("*");}}System.out.print("n");}for (k = n / 2 + 1; k <= n - n / 4; k++) {for (m = 1; m <= n + 1; m++) {if (m != n / 2)System.out.print(" ");elseSystem.out.print("|");}System.out.print("n");}}
解决方案二:
public class App { /** * @author: lance * @Title: main * @param args * @return: void */ public static void main(String[] args) { int treeHeight = 10; char treeChar = 'A'; for (int h=1; h <= treeHeight; h++) { for (int sp=1; sp <= treeHeight-h; sp++) { System.out.print(" "); } for (int t=1; t <= (2*h - 1); t++) { System.out.print(treeChar); } System.out.println(); } for (int tr=1; tr <= treeHeight/4; tr++) { for (int sp=1; sp <= treeHeight - 2; sp++) { System.out.print(" "); } System.out.print(treeChar); System.out.print(treeChar); System.out.println(treeChar); } }}