sql中取字符串中的数字语句

two:
declare @a table(id int identity(1,1),a varchar(100))
insert @a select '新会员必须购买350元产品'
union all select '新店首次定货必须满20000元'

select left(right(a,len(a)-patindex('%[0-9]%',a)+1),len(right(a,len(a)-patindex('%[0-9]%',a)+1))-1) from @a

declare @t table(s varchar(8000))

insert @t select 'aaa11112bbb'
union all select 'ccc212sss'
union all select 'sss21a'

select dbo.fn_GetNum(s) as result from @t

select substring(s,patindex('%[^0-9][0-9]%',s)+1,patindex('%[0-9][^0-9]%',s)-patindex('%[^0-9][0-9]%',s))  from @t

/*功能:获取字符串中的字母*/
CREATE FUNCTION dbo.F_Get_STR (@S VARCHAR(100))
RETURNS VARCHAR(100)
AS
BEGIN
    WHILE PATINDEX('%[^a-z]%',@S)>0
          BEGIN
                set @s=stuff(@s,patindex('%[^a-z]%',@s),1,'')
          END
    RETURN @S
END
GO
--测试
select  dbo.F_Get_STR('测试ABC123ABC')

GO

/*    
    功能:获取字符串中的数字
 */
create function dbo.F_Get_Number (@S varchar(100))
returns int
AS
begin
    while PATINDEX('%[^0-9]%',@S)>0
          begin
                set @s=stuff(@s,patindex('%[^0-9]%',@s),1,'')
          end
    return cast(@S as int)
end
--测试
---select  dbo.F_Get_Number('测试AB3C123AB5C')
GO