问题描述

c语言。

Write a program to calculate the Fibonacci sequence? The i-th element of the Fibonacci sequence is defined as follows.公式请看图 Ex)011235813
Fibonacci sequence? Input 1, input another numberto calculate the Fibonacci sequence? Input 2, show the Fibonacci sequence ? Input 3, initialization? Input 4, terminate the program

解决方案

 void PrintMenu()
{
    printf("*************
");
    printf("1. Calculate
");
    printf("2. Show it!
");
    printf("3. Initialize
");
    printf("4. Quit
");
    printf("*************
");
    printf("Input : ");
}

int main()
{
    char a;
    int b = 0;
    int i;
    int Fx = 1;
    int Fxx = 0;
    while(true)
    {
        PrintMenu();
        a = getchar();
        getchar();
        switch(a)
        {
        case '1':
            printf("Input the number : ");
            scanf("%d",&b);
            getchar();
            break;
        case '2':
            for(i=0;i<b;i++)
            {
                if(i == 0)
                    printf("%d ",Fxx);
                else if(i == 1)
                    printf("%d ",Fx);
                else
                {
                    printf("%d ",Fx+Fxx);
                    int temp = Fx;
                    Fx += Fxx;
                    Fxx = temp;
                }
            }
            printf("
");
            Fx = 1;
            Fxx = 0;
            break;
        case '3':
            b = 0;
            break;
        case '4':
            return 0;
        }
    }
    return 0;

}

解决方案二：

C语言中通过函数指针实现回调函数（Callback Function）

====== 首先使用typedef定义回调函数类型?======?
typedef void (*event_cb_t)(const struct event *evt, void *userdata);上面的语句表示event_cb_t类型函数范围值类型为void类......
答案就在这里：C语言中的回调函数

解决方案三：

 #include<stdio.h>
void printList()
{
    printf("*************
");
    printf("1. Calculate
");
    printf("2. Show it!
");
    printf("3. Initialize
");
    printf("4. Quit
");
    printf("*************
");
    printf("Input : ");
}
void nOfFab(int n)
{
    int f1 = 0;
    int f2 = 1;
    int count = 2;
    int tmp = 0;
    if(n <= 0){
        printf("
");
        return;
    }
    printf("0");
    if(n == 1){
        printf("
");
        return;
    }
    printf(" 1");
    if(n == 2){
        printf("
");
        return;
    }
    while(count < n){
        tmp = f1;
        f1 = f2;
        f2 = f1 + tmp;
        printf(" %d",f2);
        count ++;
    }
    printf("
");
}
void main()
{
    int count = 0;
    int select = 0;
    int flag = 0;
    while(!flag){
        printList();
        scanf("%d",&select);
        switch(select){
           case 1:
               printf("Input the number : ");
               scanf("%d",&count);
               break;
           case 2:
               nOfFab(count);
               break;
           case 3:
               count = 0;
               break;
           case 4:
               flag = 1;
               break;
        }
    }
}

解决方案四：

我的代码比较简洁，求采纳！

#include<stdio.h>
int PrintMenu()
{
    int a;
    printf("*************
");
    printf("1. Calculate
");
    printf("2. Show it!
");
    printf("3. Initialize
");
    printf("4. Quit
");
    printf("*************
");
    printf("Input : ");
    scanf("%d",&a);
    return a;
}
int main(){
    int n=0;
    int i;
    int f1,f2,list[300]={0};
    while(1){
        switch(PrintMenu())
        {
            case 1:
                printf("Input the number : ");
                scanf("%d",&n);
                f1=f2=1;
                for(i=1;i<=n;i++){
                    list[i]=f1;
                    f1+=f2;
                    list[++i]=f2;
                    f2+=f1;
                }
                break;
            case 2:
                for(i=0;i<n;i++)
                    printf("%d ",list[i]);
            printf("
");
                break;
            case 3:
                n=0;
                break;
            case 4:
                return 0;
        }
    }
}