问题描述

如何动态地改变 shape color?

<?xml version=""1.0"" encoding=""utf-8""?><shape xmlns:android=""http://schemas.android.com/apk/res/android""   android:shape=""rectangle"">    <solid       android:color=""#FFFF00"" />    <padding android:left=""7dp""        android:top=""7dp""        android:right=""7dp""        android:bottom=""7dp"" /></shape><TextView    android:background=""@drawable/test""    android:layout_height=""45dp""    android:layout_width=""100dp""    android:text=""Moderate""/>

现在我想根据web服务调用的信息让shape去改变颜色。所以它可能是黄色，绿色或红色或者是从web服务调用的信息中获取的颜色。

基于这些信息，如何改变shape的颜色？

解决方案

用下面的代码修改：

ShapeDrawable bgShape = (ShapeDrawable )btn.getBackground();bgShape.getPaint().setColor(Color.BLACK);

解决方案二：
GradientDrawable p = (GradientDrawable) viewHandle.subject_textview.getBackground();
p.setColor(Color.RED);

解决方案三：
GradientDrawable p = (GradientDrawable) viewHandle.subject_textview.getBackground();

p.setColor(Color.RED);

解决方案四：
在 java 中创建自己的 shapes

private void makeShapes() {    activeDrawable = new ShapeDrawable();    inactiveDrawable = new ShapeDrawable();    activeDrawable.setBounds(0 0 (int) mIndicatorSize            (int) mIndicatorSize);    inactiveDrawable.setBounds(0 0 (int) mIndicatorSize            (int) mIndicatorSize);    int i[] = new int[2];    i[0] = android.R.attr.textColorSecondary;    i[1] = android.R.attr.textColorSecondaryInverse;    TypedArray a = this.getTheme().obtainStyledAttributes(i);    Shape s1 = new OvalShape();    s1.resize(mIndicatorSize mIndicatorSize);    Shape s2 = new OvalShape();    s2.resize(mIndicatorSize mIndicatorSize);    ((ShapeDrawable) activeDrawable).getPaint().setColor(            a.getColor(0 Color.DKGRAY));    ((ShapeDrawable) inactiveDrawable).getPaint().setColor(            a.getColor(1 Color.LTGRAY));    ((ShapeDrawable) activeDrawable).setShape(s1);    ((ShapeDrawable) inactiveDrawable).setShape(s2);}

解决方案五：
根据服务器的颜色值来动态改变界面效果