总结:QL应该和导航关系结合,共同为查询提供服务。导航写全面了,QL语句就可以写的简单。
例子项目:BBS小项目
(EJBQL是HQL的子集,所以直接说是HQL也无可厚非)
Category(版块):里面有不同的主题,不同的主题有不同的发帖
Topic(主题),Msg(具体的回复帖子)
Category与Topic之间的关系是一对多(OneToMany),Topic与Msg的关系也是一对多。(OneToMany)。
具体的类:
Category.java:
package com.bjsxt.hibernate; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; @Entity public class Category { private int id; private String name; @Id @GeneratedValue public int getId() { return id; } public void setId(int id) { this.id = id; } public String getName() { return name; } public void setName(String name) { this.name = name; } }
Topic.java:
package com.bjsxt.hibernate; import java.util.Date; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.ManyToOne; @Entity public class Topic { private int id; private String title; private Category category; //private Category category2; private Date createDate; public Date getCreateDate() { return createDate; } public void setCreateDate(Date createDate) { this.createDate = createDate; } @ManyToOne(fetch=FetchType.LAZY) public Category getCategory() { return category; } public void setCategory(Category category) { this.category = category; } @Id @GeneratedValue public int getId() { return id; } public void setId(int id) { this.id = id; } public String getTitle() { return title; } public void setTitle(String title) { this.title = title; } }
Msg.java:
package com.bjsxt.hibernate; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.ManyToOne; @Entity public class Msg { private int id; private String cont; private Topic topic; @ManyToOne public Topic getTopic() { return topic; } public void setTopic(Topic topic) { this.topic = topic; } @Id @GeneratedValue public int getId() { return id; } public void setId(int id) { this.id = id; } public String getCont() { return cont; } public void setCont(String cont) { this.cont = cont; } }
MsgInfo.java:
package com.bjsxt.hibernate; public class MsgInfo { //VO DTO Value Object username p1 p2 UserInfo->User->DB private int id; private String cont; private String topicName; private String categoryName; public MsgInfo(int id, String cont, String topicName, String categoryName) { super(); this.id = id; this.cont = cont; this.topicName = topicName; this.categoryName = categoryName; } public String getTopicName() { return topicName; } public void setTopicName(String topicName) { this.topicName = topicName; } public String getCategoryName() { return categoryName; } public void setCategoryName(String categoryName) { this.categoryName = categoryName; } public int getId() { return id; } public void setId(int id) { this.id = id; } public String getCont() { return cont; } public void setCont(String cont) { this.cont = cont; } }
建表语句:
create table Category (
id integer not null auto_increment,
name varchar(255),
primary key (id)
)
create table Msg (
id integer not null auto_increment,
cont varchar(255),
topic_id integer,
primary key (id)
)
create table Topic (
id integer not null auto_increment,
createDate datetime,
title varchar(255),
category_id integer,
primary key (id)
)
alter table Msg
add index FK12F6179FADF6A (topic_id),
add constraint FK12F6179FADF6A
foreign key (topic_id)
references Topic (id)
alter table Topic
add index FK4D3DD0F8F317EEA (category_id),
add constraint FK4D3DD0F8F317EEA
foreign key (category_id)
references Category (id)
具体生成的表:
Category:id<int> name<varchar>
Msg:id<int> cont<varchar> topic_id<int>(加外键)
Topic:id<int> createDate<datetime> title<vachar> category_id<int>(加外键)
先插入一些数据:
@Test public void testSave() { Session session = sf.openSession(); session.beginTransaction(); for(int i=0; i<10; i++) { Category c = new Category(); c.setName("c" + i); session.save(c); } for(int i=0; i<10; i++) { Category c = new Category(); c.setId(1); Topic t = new Topic(); t.setCategory(c); t.setTitle("t" + i); t.setCreateDate(new Date()); session.save(t); } for(int i=0; i<10; i++) { Topic t = new Topic(); t.setId(1); Msg m = new Msg(); m.setCont("m" + i); m.setTopic(t); session.save(m); } session.getTransaction().commit(); session.close(); }
存储了10个版块,版块1有10个主题,版块1的主题1有10个帖子。
下面进行查询:
——————————————————————————————————————
@Test public void testHQL_01() { Session session = sf.openSession(); session.beginTransaction(); Query q = session.createQuery("from Category"); List<Category> categories = (List<Category>)q.list(); for(Category c : categories) { System.out.println(c.getName()); } session.getTransaction().commit(); session.close(); }
用的是import org.hibernate.Query;
而不是jpa的Query:import javax.persistence.Query;
测试结果:
Hibernate:
select
category0_.id as id0_,
category0_.name as name0_
from
Category category0_
c0
c1
c2
c3
c4
c5
c6
c7
c8
c9
注意HQL是面向对象的语言,要写类名而不是表名!!!!
——————————————————————————————————————
@Test public void testHQL_02() { Session session = sf.openSession(); session.beginTransaction(); Query q = session.createQuery("from Category c where c.name > 'c5'"); List<Category> categories = (List<Category>)q.list(); for(Category c : categories) { System.out.println(c.getName()); } session.getTransaction().commit(); session.close(); }
测试结果:
Hibernate:
select
category0_.id as id0_,
category0_.name as name0_
from
Category category0_
where
category0_.name>'c5'
c6
c7
c8
c9
因为HQL调试比较麻烦,所以就要观察它输出的sql语句
——————————————————————————————————————
@Test public void testHQL_03() { Session session = sf.openSession(); session.beginTransaction(); Query q = session.createQuery("from Category c order by c.name desc"); List<Category> categories = (List<Category>)q.list(); for(Category c : categories) { System.out.println(c.getName()); } session.getTransaction().commit(); session.close(); }
测试结果:
Hibernate:
select
category0_.id as id0_,
category0_.name as name0_
from
Category category0_
order by
category0_.name desc
c9
c8
c7
c6
c5
c4
c3
c2
c1
c0
——————————————————————————————————————
@Test public void testHQL_04() { Session session = sf.openSession(); session.beginTransaction(); Query q = session.createQuery("select distinct c from Category c order by c.name desc"); List<Category> categories = (List<Category>)q.list(); for(Category c : categories) { System.out.println(c.getName()); } session.getTransaction().commit(); session.close(); }
测试结果:
Hibernate:
select
distinct category0_.id as id0_,
category0_.name as name0_
from
Category category0_
order by
category0_.name desc
c9
c8
c7
c6
c5
c4
c3
c2
c1
c0
解释:distinct相当于互相之间不会重复,现在说的是对象不会重复(即是主键不同),这里没有变化。
——————————————————————————————————————
@Test public void testHQL_05() { Session session = sf.openSession(); session.beginTransaction(); //1.非链式编程 /*Query q = session.createQuery("from Category c where c.id > :min and c.id < :max"); //q.setParameter("min", 2); //q.setParameter("max", 8); q.setInteger("min", 2); q.setInteger("max", 8);*/ //2.链式编程 Query q = session.createQuery("from Category c where c.id > :min and c.id < :max") .setInteger("min", 2) .setInteger("max", 8); List<Category> categories = (List<Category>)q.list(); for(Category c : categories) { System.out.println(c.getId() + "-" + c.getName()); } session.getTransaction().commit(); session.close(); }
解释:Query中的“:”是占位符,由后面的setParameter等方法指定“:”后的参数。
测试结果:
Hibernate:
select
category0_.id as id0_,
category0_.name as name0_
from
Category category0_
where
category0_.id>?
and category0_.id<?
3-c2
4-c3
5-c4
6-c5
7-c6
测试2:
@Test public void testHQL_06() { Session session = sf.openSession(); session.beginTransaction(); Query q = session.createQuery("from Category c where c.id > ? and c.id < ?"); q.setParameter(0, 2) .setParameter(1, 8);//链式编程 // q.setParameter(1, 8); List<Category> categories = (List<Category>)q.list(); for(Category c : categories) { System.out.println(c.getId() + "-" + c.getName()); } session.getTransaction().commit(); session.close(); }
结果与上面相同,只不过占位符变成了"?",用数字指占位符的位置(从0开始)。
——————————————————————————————————————
分页测试:
指定分多少页,每页多少条。
@Test public void testHQL_07() { Session session = sf.openSession(); session.beginTransaction(); Query q = session.createQuery("from Category c order by c.name desc"); q.setMaxResults(4);//设定最大的结果集,每页4条 q.setFirstResult(2);//从第二条开始 List<Category> categories = (List<Category>)q.list(); for(Category c : categories) { System.out.println(c.getId() + "-" + c.getName()); } session.getTransaction().commit(); session.close(); }
测试结果:
Hibernate:
select
category0_.id as id0_,
category0_.name as name0_
from
Category category0_
order by
category0_.name desc limit ?,
?
8-c7
7-c6
6-c5
5-c4
——————————————————————————————————————
@Test public void testHQL_08() { Session session = sf.openSession(); session.beginTransaction(); Query q = session.createQuery("select c.id, c.name from Category c order by c.name desc"); List<Object[]> categories = (List<Object[]>)q.list(); for(Object[] o : categories) { //这里有自动装箱 System.out.println(o[0] + "-" + o[1]); } session.getTransaction().commit(); session.close(); }
测试结果:
Hibernate:
select
category0_.id as col_0_0_,
category0_.name as col_1_0_
from
Category category0_
order by
category0_.name desc
10-c9
9-c8
8-c7
7-c6
6-c5
5-c4
4-c3
3-c2
2-c1
1-c0
转换出来之后是一个对象数组。
——————————————————————————————————————
两张表联合查询:
面向对象的导航类型的query语言
//设定fetch type 为lazy后将不会有第二条sql语句(去查询Category)
@Test public void testHQL_09() { Session session = sf.openSession(); session.beginTransaction(); Query q = session.createQuery("from Topic t where t.category.id = 1"); List<Topic> topics = (List<Topic>)q.list(); for(Topic t : topics) { System.out.println(t.getTitle()); } session.getTransaction().commit(); session.close(); }
测试结果:
Hibernate:
select
topic0_.id as id2_,
topic0_.category_id as category4_2_,
topic0_.createDate as createDate2_,
topic0_.title as title2_
from
Topic topic0_
where
topic0_.category_id=1
t0
t1
t2
t3
t4
t5
t6
t7
t8
t9
这是著名的"1+n"问题,面试中经常问到。
——————————————————————————————————————
导航之后再导航:
@Test public void testHQL_11() { Session session = sf.openSession(); session.beginTransaction(); Query q = session.createQuery("from Msg m where m.topic.category.id = 1"); for(Object o : q.list()) { Msg m = (Msg)o; System.out.println(m.getCont()); } session.getTransaction().commit(); session.close(); }
测试结果:
Hibernate:
select
msg0_.id as id1_,
msg0_.cont as cont1_,
msg0_.topic_id as topic3_1_
from
Msg msg0_ cross
join
Topic topic1_
where
msg0_.topic_id=topic1_.id
and topic1_.category_id=1
Hibernate:
select
topic0_.id as id2_0_,
topic0_.category_id as category4_2_0_,
topic0_.createDate as createDate2_0_,
topic0_.title as title2_0_
from
Topic topic0_
where
topic0_.id=?
m0
m1
m2
m3
m4
m5
m6
m7
m8
m9
其实就相当于取了版块为1的里面的所有的帖子。他怎么知道哪个和哪个连接呢?那是因为你在实体类中导航了(MangToOne等)。
——————————————————————————————————————
生成了一个自己的类(对象)去接收信息(往往用来生成报表)。
MsgInfo.java:
package com.bjsxt.hibernate; public class MsgInfo { //VO DTO Value Object username p1 p2 UserInfo->User->DB private int id; private String cont; private String topicName; private String categoryName; public MsgInfo(int id, String cont, String topicName, String categoryName) { super(); this.id = id; this.cont = cont; this.topicName = topicName; this.categoryName = categoryName; } public String getTopicName() { return topicName; } public void setTopicName(String topicName) { this.topicName = topicName; } public String getCategoryName() { return categoryName; } public void setCategoryName(String categoryName) { this.categoryName = categoryName; } public int getId() { return id; } public void setId(int id) { this.id = id; } public String getCont() { return cont; } public void setCont(String cont) { this.cont = cont; } }
测试代码:
//了解即可 //VO Value Object(VO对象,用来装临时的值) //DTO data transfer object @Test public void testHQL_12() { Session session = sf.openSession(); session.beginTransaction(); Query q = session.createQuery("select new com.bjsxt.hibernate.MsgInfo(m.id, m.cont, m.topic.title, m.topic.category.name) from Msg"); for(Object o : q.list()) { MsgInfo m = (MsgInfo)o; System.out.println(m.getCont()); } session.getTransaction().commit(); session.close(); }
测试结果:
。。。。。。
——————————————————————————————————————
带关联关系的查询:
//动手测试left right join //为什么不能直接写Category名,而必须写t.category //因为有可能存在多个成员变量(同一个类),需要指明用哪一个成员变量的连接条件来做连接 @Test public void testHQL_13() { Session session = sf.openSession(); session.beginTransaction(); Query q = session.createQuery("select t.title, c.name from Topic t join t.category c "); //join Category c for(Object o : q.list()) { Object[] m = (Object[])o; System.out.println(m[0] + "-" + m[1]); } session.getTransaction().commit(); session.close(); }
测试结果:
Hibernate:
select
topic0_.title as col_0_0_,
category1_.name as col_1_0_
from
Topic topic0_
inner join
Category category1_
on topic0_.category_id=category1_.id
t0-c0
t1-c0
t2-c0
t3-c0
t4-c0
t5-c0
t6-c0
t7-c0
t8-c0
t9-c0
——————————————————————————————————————
//学习使用uniqueResult(返回唯一的结果,不要用list去循环了) @Test public void testHQL_14() { Session session = sf.openSession(); session.beginTransaction(); Query q = session.createQuery("from Msg m where m = :MsgToSearch "); //不重要 Msg m = new Msg(); m.setId(1); q.setParameter("MsgToSearch", m); Msg mResult = (Msg)q.uniqueResult(); System.out.println(mResult.getCont()); session.getTransaction().commit(); session.close(); }
设定一个对象,让HQL语句去找符合这个对象的记录,很像QBE,用的不多
测试结果:
Hibernate:
select
msg0_.id as id1_,
msg0_.cont as cont1_,
msg0_.topic_id as topic3_1_
from
Msg msg0_
where
msg0_.id=?
Hibernate: //设@ManyToOne(fetch=FetchType.LAZY)就不出这一句了
select
topic0_.id as id2_0_,
topic0_.category_id as category4_2_0_,
topic0_.createDate as createDate2_0_,
topic0_.title as title2_0_
from
Topic topic0_
where
topic0_.id=?
m0
——————————————————————————————————————
@Test public void testHQL_15() { Session session = sf.openSession(); session.beginTransaction(); Query q = session.createQuery("select count(*) from Msg m"); long count = (Long)q.uniqueResult(); System.out.println(count); session.getTransaction().commit(); session.close(); }
测试结果:
Hibernate:
select
count(*) as col_0_0_
from
Msg msg0_
10
——————————————————————————————————————
@Test public void testHQL_16() { Session session = sf.openSession(); session.beginTransaction(); Query q = session.createQuery("select max(m.id), min(m.id), avg(m.id), sum(m.id) from Msg m"); Object[] o = (Object[])q.uniqueResult(); System.out.println(o[0] + "-" + o[1] + "-" + o[2] + "-" + o[3]); session.getTransaction().commit(); session.close(); }
测试结果:
Hibernate:
select
max(msg0_.id) as col_0_0_,
min(msg0_.id) as col_1_0_,
avg(msg0_.id) as col_2_0_,
sum(msg0_.id) as col_3_0_
from
Msg msg0_
10-1-5.5-55
——————————————————————————————————————
@Test public void testHQL_17() { Session session = sf.openSession(); session.beginTransaction(); Query q = session.createQuery("from Msg m where m.id between 3 and 5"); for(Object o : q.list()) { Msg m = (Msg)o; System.out.println(m.getId() + "-" + m.getCont()); } session.getTransaction().commit(); session.close(); }
测试结果:
Hibernate:
select
msg0_.id as id1_,
msg0_.cont as cont1_,
msg0_.topic_id as topic3_1_
from
Msg msg0_
where
msg0_.id between 3 and 5
Hibernate: //设@ManyToOne(fetch=FetchType.LAZY)就不出这一句了
select
topic0_.id as id2_0_,
topic0_.category_id as category4_2_0_,
topic0_.createDate as createDate2_0_,
topic0_.title as title2_0_
from
Topic topic0_
where
topic0_.id=?
3-m2
4-m3
5-m4
——————————————————————————————————————
@Test public void testHQL_18() { Session session = sf.openSession(); session.beginTransaction(); Query q = session.createQuery("from Msg m where m.id in (3,4, 5)"); for(Object o : q.list()) { Msg m = (Msg)o; System.out.println(m.getId() + "-" + m.getCont()); } session.getTransaction().commit(); session.close(); }
测试结果:
Hibernate:
select
msg0_.id as id1_,
msg0_.cont as cont1_,
msg0_.topic_id as topic3_1_
from
Msg msg0_
where
msg0_.id in (
3 , 4 , 5
)
Hibernate: //设@ManyToOne(fetch=FetchType.LAZY)就不出这一句了
select
topic0_.id as id2_0_,
topic0_.category_id as category4_2_0_,
topic0_.createDate as createDate2_0_,
topic0_.title as title2_0_
from
Topic topic0_
where
topic0_.id=?
3-m2
4-m3
5-m4
——————————————————————————————————————
//is null 与 is not null @Test public void testHQL_19() { Session session = sf.openSession(); session.beginTransaction(); Query q = session.createQuery("from Msg m where m.cont is not null"); for(Object o : q.list()) { Msg m = (Msg)o; System.out.println(m.getId() + "-" + m.getCont()); } session.getTransaction().commit(); session.close(); }
测试结果:
Hibernate:
select
msg0_.id as id1_,
msg0_.cont as cont1_,
msg0_.topic_id as topic3_1_
from
Msg msg0_
where
msg0_.cont is not null
Hibernate: //设@ManyToOne(fetch=FetchType.LAZY)就不出这一句了
select
topic0_.id as id2_0_,
topic0_.category_id as category4_2_0_,
topic0_.createDate as createDate2_0_,
topic0_.title as title2_0_
from
Topic topic0_
where
topic0_.id=?
1-m0
2-m1
3-m2
4-m3
5-m4
6-m5
7-m6
8-m7
9-m8
10-m9
余下的请看《EJBQL第二部分》
转载请注明出处:http://blog.csdn.net/acmman/article/details/43917099