问题描述
用OpenFileDialogopenFileDialog1=newOpenFileDialog()...打开文件后,如何获取当前文件的完整路径??
解决方案
解决方案二:
openFileDialog1.FileName;
解决方案三:
stringfullname=openFileDialog1.FileName;stringpath=System.IO.Path.GetDirectoryName(fullname);
解决方案四:
OpenFileDialogm_OpenFileDialog=newOpenFileDialog();m_OpenFileDialog.Title="打开文件";m_OpenFileDialog.Filter="所有文件(*.*)|*.*";m_OpenFileDialog.FilterIndex=1;m_OpenFileDialog.RestoreDirectory=true;m_OpenFileDialog.Multiselect=false;if(DialogResult.OK==m_OpenFileDialog.ShowDialog()){tbFilePath.Text=m_OpenFileDialog.FileName;}
解决方案五:
引用1楼zhlu880516的回复:
openFileDialog1.FileName;
解决方案六:
引用1楼zhlu880516的回复:
openFileDialog1.FileName;
解决方案七:
用System.IO.Path类的GetDirectoryName()方法就可以做到获取文件路径
解决方案八:
stringfullname=openFileDialog1.FileName;stringpath=System.IO.Path.GetDirectoryName(fullname);
解决方案九:
引用3楼xrascal的回复:
OpenFileDialogm_OpenFileDialog=newOpenFileDialog();m_OpenFileDialog.Title="打开文件";m_OpenFileDialog.Filter="所有文件(*.*)¦*.*";m_OpenFileDialog.FilterIndex=1;m_OpenFileDialog.RestoreDirectory=true;m_OpenFileDialog.Multiselect=false;if(DialogResult.OK==m_OpenFileDialog.ShowDialog()){tbFilePath.Text=m_OpenFileDialog.FileName…
解决方案十:
m_OpenFileDialog.FileName
解决方案十一:
Nod
解决方案十二:
FileName