原文 http://www.csharp-examples.net/xml-nodes-by-name/
To find nodes in an XML file you can use XPath expressions. Method XmlNode.SelectNodes returns a list of nodes selected by the XPath string. Method XmlNode.SelectSingleNode finds the first node that matches the XPath string.
Suppose we have this XML file.
[XML]
<Names> <Name> <FirstName>John</FirstName> <LastName>Smith</LastName> </Name> <Name> <FirstName>James</FirstName> <LastName>White</LastName> </Name> </Names>
To get all <Name> nodes use XPath expression /Names/Name
. The first slash means that the <Names> node must be a root node. SelectNodes method returns collection XmlNodeList which will contain the <Name> nodes. To get value of sub node <FirstName> you can simply index XmlNode with the node name: xmlNode["FirstName"].InnerText
. See the example below.
[C#]
XmlDocument xml = new XmlDocument(); xml.LoadXml(myXmlString); // suppose that myXmlString contains "<Names>...</Names>" XmlNodeList xnList = xml.SelectNodes("/Names/Name"); foreach (XmlNode xn in xnList) { string firstName = xn["FirstName"].InnerText; string lastName = xn["LastName"].InnerText; Console.WriteLine("Name: {0} {1}", firstName, lastName); }
The output is:
Name: John Smith Name: James White
时间: 2024-10-31 10:12:30