使用Python简单的发送邮件

#来源忘了，就不贴链接地址了

#简单的python smtp发邮件代码

import smtplib
from email.mime.text import MIMEText

mailto_list=["123456789@qq.com","987654321@qq.com"]

mail_host="smtp.qq.com"
mail_user="123456789@qq.com"
mail_pass="***************"
mail_postfix="qq.com"

def send_mail(to_list,sub,content):
    '''
    to_list:发给谁
    sub:主题
    content:内容
    send_mail("aaa@126.com","sub","content")
    '''
    me=mail_user+"<"+mail_user+"@"+mail_postfix+">"
    msg=MIMEText(content)
    msg['Subject']=sub
    msg['From']=me
    msg['To']=";".join(to_list)
    try:
        s=smtplib.SMTP(port=465)
        s.connect(mail_host)
        s.login(mail_user,mail_pass)
        s.sendmail(me, to_list,msg.as_string())
        s.close()
        return True
    except Exception, e:
        print str(e)
        return False
    
if __name__ == '__main__':
    sub="hello baby(python test mail)"
    content="乔装打扮，不择手段"
    if send_mail(mailto_list,sub,content):
        print "发送成功"
    else:
        print "发送失败"