//完善的学生成绩计算统计；kkkpo
//注意多留一个存储单元 i=0开始
#include<iostream.h>
#include<string.h>
const int N=100;
const int M=14;
const int P=30;
void array_in(int n,int m,float score[][M],char num[][P],char name[][P]);
void dzhongcj(int n,int m,float score[][M],char num[][P],char name[][P]);//每个学生的总成绩shuchu
void fencheng(int n,int m,float score[][M],char num[][P],char name[][P]);//成绩分层
void zaverage(int n,int m,float score[][M],char num[][P],char name[][P]);//总平均值
void average(int n,int m,float score[][M],char num[][P],char name[][P]);//每科平均成绩
void dankepx(int n,int m,float score[][M],char num[][P],char name[][P]);//单科排序
void zhongzjpx(int n,int m,float score[][M],char num[][P],char name[][P]);//总成绩排序
void taverage(int n,int m,float score[][M],char num[][P],char name[][P]);//单个同学平均成绩
void caizao(int n,int m,float score[][M],char num[][P],char name[][P]);//同学成绩查找；
void dankez(int n,int m,float score[][M],char num[][P],char name[][P]);//单科最优成绩
void zongz(int n,int m,float score[][M],char num[][P],char name[][P]);//总成绩最优成绩
void yxhxs(int n,int m,float score[][M],char num[][P],char name[][P]);//以学号形式查找信息
void yxhxs(int n,float x[],char num[][P],char name[][P]);
void yxmxs(int n,int m,float score[][M],char num[][P],char name[][P]);//以名字形式查找
void axmdx(int n,int m,float score[][M],char num[][P],char name[][P]);//按姓名大小排序
void axmdx(int n,float x[],char num[][P],char name[][P]);
void yxmxs(int n,float x[],char str[],char num[][P],char name[][P]);
float max(float [],int n);
float mix(float [],int n);
float average(float [],int n);
void fenceng(float [],int n,char num[][P],char name[][P]);
void lcp(float x[],int n,char num[][P],char name[][P],char str[]);
void caizao(float x[],int n,char num[][P],char name[][P]);
void mian(void);
void miin(void)
{
int n,m,k;
char str[N];
float score[N][M];
char num[N][P];
char name[N][P];
char x='y';
cin.get();
cout<<endl;
cout<<"要进行成绩处理输入任意键否则N或n";
cin>>x;
while(x!='N'&&x!='n')
{
cout<<"班级:";
cin>>str;
cout<<"参考人数n=";
cin>>n;
cout<<"科目 m=";
cin>>m;
array_in(n,m,score,num,name);
cin.get();
while(x!='N'&&x!='n')
{
cout<<"每个学生的总成绩(1) 成绩评优(2) 总平均成绩值(3)"<<endl;
cout<<"单科平均成绩 (4) 单科排序(5) 总成绩排序 (6)"<<endl;
cout<<"同学平均成绩 (7) 同学成绩查找(8) 单科最优成绩(9)"<<endl;
cout<<"总成绩最优成绩 (10) 按姓名大小排序(11)(总体情况咨询)"<<endl;
cout<<"请选择k(1—14)=";
cin>>k;//注意；着两个的区别
//k=cin.get();//
switch(k)
{
case 1: dzhongcj( n,m,score,num,name);
break;
case 2: fencheng(n,m,score,num,name);
break;
case 3: zaverage(n,m,score,num,name);
break;
case 4: average(n,m,score,num,name);
break;
case 5: dankepx(n,m,score,num,name);
break;
case 6: zhongzjpx(n,m,score,num,name);
break;
case 7: taverage(n,m,score,num,name);
break;
case 8: caizao(n,m,score,num,name);
break;
case 9: dankez(n,m,score,num,name);
break;
case 10: zongz(n,m,score,num,name);
break;
case 11: axmdx(n,m,score,num,name);
break;
}
cout<<endl;
cout<<"要继续进行该班成绩处理输入任意键否则N或n";
cin>>x;
cout<<endl;
}
cout<<endl;
cout<<"要继续进行另一班成绩处理输入任意键否则N或n";
cin>>x;
}
}
void array_in(int n,int m,float score[][M],char num[][P],char name[][P])
{
int i,j;
for(i=0;i<n;i++)
{
cout<<"学号 ";
cin>>num[i];
cout<<"姓名 ";
cin>>name[i];
for(j=0;j<m;j++)
{
cout<<"分数"<<j+1<<"=";
cin>>score[i][j];
}
}
}
void dzhongcj(int n,int m,float score[][M],char num[][P],char name[][P])//每个学生的总成绩
{
int i,j;
float sum=0;
cout<<endl;
cout<<" <<每个学生的总成绩>> "<<endl;
cout<<endl;
for(i=0;i<n;i++)
{
sum=0;//赋初值为0；
cout<<"学号 "<<num[i]<<" 姓名 "<<name[i]<<" 分数 ";
for(j=0;j<m;j++)
{
{
cout<<score[i][j]<<" ";
sum+=score[i][j];
}
}
cout<<"总分:"<<sum<<endl;
}
cout<<endl;
}
void fencheng(int n,int m,float score[][M],char num[][P],char name[][P])//成绩分层
{
int i,j,k,B;
double b;
char x='y';
float sum=0;
cout<<endl;
cout<<" <<成绩评优>> "<<endl;
cout<<endl;
while(x!='N'&&x!='n')
{
cout<<endl;
cout<<"总成绩分层（1） 单科分成（2）";
cin>>k;
cout<<endl;
switch(k)
{
case 1:
{
for(i=0;i<n;i++)
{
sum=0;
for(j=0;j<m;j++)
sum+=score[i][j];
score[i][m]=sum;
}
for(i=0;i<n;i++)
{
sum=score[i][m];
if(m>1)
{ b=sum/100.0;
if(b<=m&&b>=(0.9*m))
cout<<"学号 "<<num[i]<<" 姓名 "<<name[i]<<" "<<" 非常优秀!"<<endl;
else if(b>=(0.8*m)&&b<(0.9*m))
cout<<"学号 "<<num[i]<<" 姓名 "<<name[i]<<" "<<" 良好!"<<endl;
else if(b<(0.8*m)&&b>=(0.6*m))
cout<<"学号 "<<num[i]<<" 姓名 "<<name[i]<<" "<<" 及格!"<<endl;
else
cout<<"学号 "<<num[i]<<" 姓名 "<<name[i]<<" "<<" 不及格!"<<endl;
}
if(m==1)
{
B=int(sum/10);
switch(B)
{
case 10:
case 9: cout<<"学号"<<num[i]<<" 姓名 "<<name[i]<<" 非常优秀!"<<endl;
break;
case 8:
case 7: cout<<"学号"<<num[i]<<" 姓名 "<<name[i]<<" 优良!"<<endl;
break;
case 6: cout<<"学号"<<num[i]<<" 姓名 "<<name[i]<<" 及格!"<<endl;
break;
case 5:
case 4:
case 3:
case 2:
case 1:
case 0: cout<<"学号"<<num[i]<<" 姓名 "<<name[i]<<" 不及格!"<<endl;
break;
}
}
}
cout<<endl;
}
break;
case 2:
{
while(x!='N'&&x!='n')
{
cout<<endl;
cout<<"请输入科目j的j=";
cin>>j;
cout<<endl;
for(i=0;i<n;i++)
{
B=int(score[i][j-1]/10);//注意；[j-1]
switch(B)
{
case 10:
case 9: cout<<"学号"<<num[i]<<" 姓名 "<<name[i]<<" 非常优秀!"<<endl;
break;
case 8:
case 7: cout<<"学号"<<num[i]<<" 姓名 "<<name[i]<<" 优良!"<<endl;
break;
case 6: cout<<"学号"<<num[i]<<" 姓名 "<<name[i]<<" 及格!"<<endl;
break;
case 5:
case 4:
case 3:
case 2:
case 1:
case 0: cout<<"学号"<<num[i]<<" 姓名 "<<name[i]<<"不及格!"<<endl;
break;
}
}
cout<<endl;
cout<<"要继续进行单科成绩评优输入任意键否则N或n";
cin>>x;
cout<<endl;
}
break;
}
}
cout<<endl;
cout<<"要继续进行成绩评优输入任意键否则N或n";
cin>>x;
}
cout<<endl;
}
void zaverage(int n,int m,float score[][M],char num[][P],char name[][P])//总平均值
{
int i;
int j;
float sun=0;
float sum;
float sco[1000];
cout<<endl;
cout<<"<<总平均成绩值>>"<<endl;
cout<<endl;
for(i=0;i<n;i++)
{
sum=0;
for(j=0;j<m;j++)
{
sum+=score[i][j];
}
sco[i]=sum;
}
for(i=0;i<n;i++)
{
sun+=sco[i];
cout<<"学号 "<<num[i]<<" 姓名 "<<name[i]<<" "<<" 总分数 "<<sco[i]<<" "<<endl;
}
cout<<"总平均成绩 "<<sun/n<<endl;//注意；复职方式
cout<<endl;
}
void average(int n,int m,float score[][M],char num[][P],char name[][P])//每科平均成绩
{
int i,j;
float sum=0;
char x='y';
cout<<endl;
cout<<"<<每科平均成绩>>"<<endl;
cout<<endl;
while(x!='N'&&x!='n')
{
cout<<endl;
cout<<"请输入科目j的j=";
cin>>j;
for(i=0;i<n;i++)
{
cout<<"学号 "<<num[i]<<" 姓名 "<<name[i]<<" "<<" 分数 "<<score[i][j-1]<<endl;
sum+=score[i][j-1];//注意[j-1];
}
cout<<"该单科平均成绩:"<<sum/n<<endl;
cout<<endl;
cout<<"要继续进行单科平均值输入任意键否则N或n";
cin>>x;
}
cout<<endl;
}
void dankepx(int n,int m,float score[][M],char num[][P],char name[][P])//单科排序
{
int i,j,k;
char x='y';
float sco;
char nu[P];
char na[P];
float sum=0;
cout<<endl;
cout<<"<<单科成绩排序>>"<<endl;
cout<<endl;
while(x!='N'&&x!='n')
{
cout<<"输入单科代号j=";
cin>>j;
for(i=0;i<n;i++)
{
sum+=score[i][j-1];
for(k=i+1;k<n;k++)
{
if(score[i][j-1]<score[k][j-1])
{
sco=score[i][j-1];//注意这里是j-1;
score[i][j-1]=score[k][j-1];
score[k][j-1]=sco;
strcpy(na,name[i]);
strcpy(name[i],name[k]);
strcpy(name[k],na);
strcpy(nu,num[i]);
strcpy(num[i],num[k]);
strcpy(num[k],nu);
}
}
}
for(i=0;i<n;i++)
cout<<"学号 "<<num[i]<<" 姓名 "<<name[i]<<" 分数 "<<score[i][j-1]<<endl;
score[n][j-1]=sum/n;
cout<<"这科平均分 "<<score[n][j-1]<<endl;
cout<<endl;
cout<<"要继续单科排序输入任意键否则N或n";
cin>>x;
}
cout<<endl;
}
void zhongzjpx(int n,int m,float score[][M],char num[][P],char name[][P])//总成绩排序
{
int i,j,k;
float sum;
float max;
char nu[P];
char na[P];
float sco;//注意；成绩是单个的 所以sco不要定义为数组
if(n==1)
for(j=0;j<m;j++)
cout<<"学号"<<num[0]<<" 姓名 "<<name[0]<<" "<<" "<<score[1][j]<<" "<<score[0][m]<<endl;
if(n==2)
{
if(score[0][m]<score[1][m])
{
for(j=0;j<m;j++)
cout<<"学号"<<num[1]<<" 姓名 "<<name[1]<<" "<<"总分 "<<score[1][j]<<" "<<score[1][m]<<endl;
cout<<endl;
for(j=0;j<m;j++)
cout<<"学号"<<num[0]<<" 姓名 "<<name[0]<<" "<<"总分 "<<score[0][j]<<" "<<score[0][m]<<endl;
cout<<endl;
}
else
{
cout<<"学号"<<num[0]<<" 姓名 "<<name[0]<<" ";
for(j=0;j<m;j++)
{
cout<<score[0][j]<<" ";
}
cout<<"总分 "<<score[0][m]<<endl;
cout<<"学号"<<num[1]<<" 姓名 "<<name[1]<<" "<<" ";
for(j=0;j<m;j++)
{
cout<<score[1][j]<<" ";
}
cout<<"总分 "<<score[1][m]<<endl;
}
}
else
{
for(i=0;i<n;i++)
{
sum=0;//每次副初值为0；
for(j=0;j<m;j++)
sum+=score[i][j];
score[i][m]=sum;
}
for(i=0;i<n-1;i++)
for(k=i+1;k<n;k++)
{
if(score[i][m]<score[k][m])
{
max=score[i][m];
score[i][m]=score[k][m];
score[k][m]=max;
strcpy(na,name[i]);//na=name[i+1];/////////////字符串的复制
strcpy(name[i],name[k]);//name[i+1]=name[i+2];
strcpy(name[k],na);//name[i+2]=na;
strcpy(nu,num[i]);//nu=num[i+1];
strcpy(num[i],num[k]);//num[i+1]=num[i+2];
strcpy(num[k],nu);//num[i+2]=num[i+1];
for(j=0;j<m;j++)
{
sco=score[i][j];
score[i][j]=score[k][j];
score[k][j]=sco;
}
/*if(score[i+1][m]>score[i][m])
{
max=score[i][m];
score[i][m]=score[i+1][m];
score[i+1][m]=max;
strcpy(na,name[i]);//na=name[i];
strcpy(name[i],name[i+1]);//name[i]=name[i+1];
strcpy(name[i+1],na);//name[i+1]=na;
strcpy(nu,num[i]);//nu=num[i];
strcpy(num[i],num[i+1]);//num[i]=num[i+1];
strcpy(num[i+1],nu);//num[i+1]=nu;
for(j=0;j<m;j++)
{
sco=score[i][j];
score[i][j]=score[i+1][j];
score[i+1][j]=sco;
}
}*/
}
}
for(i=0;i<n;i++)
{
cout<<"学号"<<num[i]<<" 姓名 "<<name[i]<<" 分数 ";
for(j=0;j<m;j++)
{
cout<<" "<<score[i][j];
}
cout<<" 总分 "<<score[i][m]<<endl;
}
}
}
void taverage(int n,int m,float score[][M],char num[][P],char name[][P])//单个同学平均成绩
{
int i,j;
float sum;
cout<<endl;
cout<<"<<同学平均成绩>>"<<endl;
cout<<endl;
for(i=0;i<n;i++)
{
sum=0;//每次副初值为0；
for(j=0;j<m;j++)
sum+=score[i][j];
score[i][m]=sum;
}
for(i=0;i<n;i++)
{
cout<<"学号"<<num[i]<<" 姓名 "<<name[i]<<" 分数 ";
for(j=0;j<m;j++)
cout<<score[i][j]<<" ";
cout<<" 平均分 "<<(score[i][m]/m)<<endl;
}
cout<<endl;
}
void caizao(int n,int m,float score[][M],char num[][P],char name[][P])//同学成绩查找；
{
int k;
char p='y';
cout<<endl;
cout<<"<<同学信息查找>>"<<endl;
cout<<endl;
while(p!='N'&&p!='n')
{
cout<<endl;
cout<<"以学号形式输入（1）或以姓名形式输入（2）";
cin>>k;
switch(k)
{
case 1: yxhxs(n,m,score,num,name);
break;
case 2: yxmxs(n,m,score,num,name);
break;
}
cout<<endl;
cout<<"要继续进行同学信息查找输入任意键否则N或n";
cin>>p;
}
cout<<endl;
}
void dankez(int n,int m,float score[][M],char num[][P],char name[][P])//单科最优成绩
{
int i,j;
int k;
char nu[P];
char na[P];
float sco;
char x='y';
cout<<endl;
cout<<"<<某一单科最优成绩>>"<<endl;
cout<<endl;
while(x!='N'&&x!='n')
{
cout<<endl;
cout<<"输入单科代号j=";
cin>>j;
for(i=0;i<n;i++)
{
for(k=i+1;k<n;k++)
{
if(score[i][j-1]<score[k][j-1])
{
sco=score[i][j-1];//注意这里是j-1;
score[i][j-1]=score[k][j-1];
score[k][j-1]=sco;
strcpy(na,name[i]);
strcpy(name[i],name[k]);
strcpy(name[k],na);
strcpy(nu,num[i]);
strcpy(num[i],num[k]);
strcpy(num[k],nu);
}
}
}
cout<<endl;
cout<<"学号 "<<num[0]<<" 姓名 "<<name[0]<<" 最优分数"<<j<<" "<<score[0][j-1]<<endl;
cout<<endl;
cout<<"要继续单科最优成绩查找输入任意键否则N或n";
cin>>x;
}
cout<<endl;
}
void zongz(int n,int m,float score[][M],char num[][P],char name[][P])//总成绩最优成绩
{
int i;
int j;
int k;
float sum;
char nu[P];
char na[P];
float sco;
cout<<endl;
cout<<"<<总成绩最优成绩>>"<<endl;
cout<<endl;
for(i=0;i<n;i++)
{
sum=0;//每次副初值为0；
for(j=0;j<m;j++)
sum+=score[i][j];
score[i][m]=sum;
}
for(i=0;i<n;i++)
for(k=i+1;k<n;k++)
{
if(score[i][m]<score[k][m])
{
sco=score[i][m];//注意这里是j-1;
score[i][m]=score[k][m];
score[k][m]=sco;
strcpy(na,name[i]);
strcpy(name[i],name[k]);
strcpy(name[k],na);
strcpy(nu,num[i]);
strcpy(num[i],num[k]);
strcpy(num[k],nu);
}
}
cout<<endl;
cout<<"学号 "<<num[0]<<" 姓名 "<<name[0]<<" 最优总分数 "<<score[0][m]<<endl;
cout<<endl;
}
void yxhxs(int n,int m,float score[][M],char num[][P],char name[][P])//以学号形式查找信息
{
char nu[P];
int i,j;
float b;
float sum;
float sun;
char x='y';
cout<<endl;
for(i=0;i<n;i++)
{
sun=0;
for(j=0;j<m;j++)
sun+=score[i][j];
score[i][m]=sun;
}
while(x!='N'&&x!='n')
{
cout<<endl;
cout<<"请输入学号 ";
cin>>nu;
for(i=0;i<n;i++)
{
if(strcmp(num[i],nu)==0)//用来判断两个字符串相等
{
cout<<"学号 "<<num[i]<<" 姓名 "<<name[i]<<" 分数 ";
for(j=0;j<m;j++)
cout<<score[i][j]<<" ";
cout<<"总分 "<<score[i][m]<<" ";//补充成绩分层
sum=score[i][m];
b=float(sum/100.0);
if(b<=m&&b>=(0.9*m))
cout<<" 非常优秀!"<<endl;
else if(b>=(0.8*m)&&b<(0.9*m))
cout<<" 良好!"<<endl;
else if(b<(0.8*m)&&b>=(0.6*m))
cout<<" 及格!"<<endl;
else
cout<<" 不及格!"<<endl;
}
}
cout<<endl;
cout<<"要继续进行学号形式查找学生信息按任意键否则输入N或n";
cin>>x;
}
cout<<endl;
}
void axmdx(int n,int m,float score[][M],char num[][P],char name[][P])//按姓名大小排序
{
int i,j,k;
float sun,b,sum;
char nu[P];
char na[P];
float sco;
for(i=0;i<n;i++)
{
sun=0;
for(j=0;j<m;j++)
sun+=score[i][j];
score[i][m]=sun;
}
if(n==1)
{
cout<<"学号 "<<num[0]<<" 姓名 "<<name[0]<<" ";
for(j=0;j<m;j++)
cout<<score[0][j]<<" ";
cout<<" 总分 "<<score[0][m]<<" ";
sum=score[0][m];
b=float(sum/100.0);
if(b<=m&&b>=(0.9*m))
cout<<" 非常优秀!"<<endl;
else if(b>=(0.8*m)&&b<(0.9*m))
cout<<" 良好!"<<endl;
else if(b<(0.8*m)&&b>=(0.6*m))
cout<<" 及格!"<<endl;
else
cout<<" 不及格!"<<endl;
}
else
{
for(i=0;i<n-1;i++)
for(k=i+1;k<n;k++)
{
if(strcmp(name[i],name[k])>0)
{
strcpy(na,name[i]);
strcpy(name[i],name[k]);
strcpy(name[k],na);
strcpy(nu,num[i]);
strcpy(num[i],num[k]);
strcpy(num[k],nu);
sco=score[i][m];//注意这里是j-1;
score[i][m]=score[k][m];
score[k][m]=sco;
for(j=0;j<m;j++)
{
sco=score[i][j];
score[i][j]=score[k][j];
score[k][j]=sco;
}
}
}
for(i=0;i<n;i++)
{
cout<<"学号 "<<num[i]<<" 姓名 "<<name[i]<<" 分数 ";
for(j=0;j<m;j++)
cout<<score[i][j]<<" ";
cout<<" 总分 "<<score[i][m]<<" ";
sum=score[i][m];
b=float(sum/100.0);
if(b<=m&&b>=(0.9*m))
cout<<" 非常优秀!"<<endl;
else if(b>=(0.8*m)&&b<(0.9*m))
cout<<" 良好!"<<endl;
else if(b<(0.8*m)&&b>=(0.6*m))
cout<<" 及格!"<<endl;
else
cout<<" 不及格!"<<endl;
}
}
cout<<endl;
}
void axmdx(int n,float x[],char str[],char num[][P],char name[][P])
{
int k,i;
float s;
char nu[P];
char na[P];
if(n==1)
{
cout<<"学号 "<<num[0]<<" 姓名 "<<name[0]<<" "<<str<<"分数 "<<x[0];
switch(int(x[0]/10))
{
case 10:
case 9: cout<<" 非常优秀!"<<endl;//说明输出一定要放在最后面
break;
case 8:
case 7: cout<<" 优良!"<<endl;
break;
case 6: cout<<" 及格!"<<endl;
break;
case 5:
case 4:
case 3:
case 2:
case 1:
case 0: cout<<" 不及格!"<<endl;
break;
}
}
else
{
for(i=0;i<n-1;i++)
for(k=i+1;k<n;k++)
{
if(strcmp(name[i],name[k])>0)
{
strcpy(na,name[i]);
strcpy(name[i],name[k]);
strcpy(name[k],na);
strcpy(nu,num[i]);
strcpy(num[i],num[k]);
strcpy(num[k],nu);
s=x[i];
x[i]=x[k];
x[k]=s;
}
}
for(i=0;i<n;i++)
{
cout<<"学号 "<<num[i]<<" 姓名 "<<name[i]<<" "<<str<<"分数 "<<x[i];
switch(int(x[i]/10))
{
case 10:
case 9: cout<<" 非常优秀!"<<endl;//说明输出一定要放在最后面
break;
case 8:
case 7: cout<<" 优良!"<<endl;
break;
case 6: cout<<" 及格!"<<endl;
break;
case 5:
case 4:
case 3:
case 2:
case 1:
case 0: cout<<" 不及格!"<<endl;
break;
}
}
}
cout<<endl;
}
void yxmxs(int n,int m,float score[][M],char num[][P],char name[][P])
{
char na[P];
int i,j;
float b;
float sum;
float sun;
char x='y';
cout<<endl;
for(i=0;i<n;i++)
{
sun=0;
for(j=0;j<m;j++)
sun+=score[i][j];
score[i][m]=sun;
}
while(x!='N'&&x!='n')
{
cout<<endl;
cout<<"请输入姓名 ";
cin>>na;
for(i=0;i<n;i++)
{
if(strcmp(name[i],na)==0)//用来判断两个字符串相等
{
cout<<"学号 "<<num[i]<<" 姓名 "<<name[i]<<" 分数 ";
for(j=0;j<m;j++)
cout<<score[i][j]<<" ";
cout<<"总分 "<<score[i][m]<<" ";//补充成绩分层
sum=score[i][m];
b=float(sum/100.0);
if(b<=m&&b>=(0.9*m))
cout<<" 非常优秀!"<<endl;
else if(b>=(0.8*m)&&b<(0.9*m))
cout<<" 良好!"<<endl;
else if(b<(0.8*m)&&b>=(0.6*m))
cout<<" 及格!"<<endl;
else
cout<<" 不及格!"<<endl;
}
}
cout<<endl;
cout<<"要继续进行姓名形式查找学生信息按任意键否则输入N或n";
cin>>x;
}
cout<<endl;
}
void mian()
{ int n,c,i;
float x[1000];
char s;
char str[P];
char num[N][P];
char name[N][P];
cout<<endl;
cout<<"要进行成绩输入和统计输入Ｙ或y否则N或n 选择; ";
cin>>s;
while(s!='N'&&s!='n')
{
cout<<endl;
cout<<"科目: ";
cin>>str;
cout<<"请输入学生数量n=";
cin>>n;
for(i=0;i<n;i++)
{
cout<<"学号 ";
cin>>num[i];
cout<<"姓名 ";
cin>>name[i];
cout<<"分数 ";
cin>>x[i];
}
while(s!='N'&&s!='n')
{
cout<<"寻找学生最优成绩输入(1) 最差成绩输入(2) 平均成绩输入(3)"<<endl;
cout<<"成绩评优输入(4) 成绩大小排序输入(5) 查找学生信息输入(6) "<<endl;
cout<<"按姓名大小排序(能咨询总体情况) (7)"<<endl;
cout<<"选择c(1->6)=";
cin>>c;
cout<<endl;
switch(c)
{
case 1: cout<<str<<"最优成绩: "<<max(x,n)<<endl;
break;
case 2: cout<<str<<"最差成绩: "<<mix(x,n)<<endl;
break;
case 3: cout<<str<<"平均成绩: "<<average(x,n)<<endl;//看x后面没有［］；；
break;
case 4: fenceng(x,n,num,name);
break;
case 5: lcp(x,n,num,name,str);
break;
case 6: caizao(x,n,num,name);
break;
case 7: axmdx(n,x,str,num,name);
}
cin.get();//接收回车键enter;
cout<<endl;
cout<<"是否要继续输入Ｙ或y否则N或n 选择;";
cin>>s;
}
//cin.get();//接收回车键enter;
cout<<endl;
cout<<"是否要进行另一科成绩的输入和统计输入Ｙ或y否则N或n 选择;";
cin>>s;
}
cout<<endl;
}
void lcp(float x[],int n,char num[][P],char name[][P],char str[])
{
int i,k;
float sco;
char nu[P];
char na[P];
float sum=0;
cout<<endl;
cout<<"<<单科成绩排序>>"<<endl;
cout<<endl;
for(i=0;i<n-1;i++)
{
for(k=i+1;k<n;k++)
{
if(x[i]<x[k])
{
sco=x[i];//注意这里是j-1;
x[i]=x[k];
x[k]=sco;
strcpy(na,name[i]);
strcpy(name[i],name[k]);
strcpy(name[k],na);
strcpy(nu,num[i]);
strcpy(num[i],num[k]);
strcpy(num[k],nu);
}
}
}
for(i=0;i<n;i++)
{
sum+=x[i];
cout<<"学号 "<<num[i]<<" 姓名 "<<name[i]<<" 分数 "<<x[i]<<endl;
}
cout<<str<<"平均分 "<<sum/n<<endl;
cout<<endl;
}
void fenceng(float x[],int n,char num[][P],char name[][P])
{
int i;
cout<<endl;
for(i=0;i<n;i++)
{
switch(int(x[i]/10))
{
case 10:
case 9: cout<<"学号 "<<num[i]<<" 姓名 "<<name[i]<<" 分数 "<<x[i]<<"非常优秀!"<<endl;//说明输出一定要放在最后面
break;
case 8:
case 7: cout<<"学号 "<<num[i]<<" 姓名 "<<name[i]<<" 分数 "<<x[i]<<"优良!"<<endl;
break;
case 6: cout<<"学号 "<<num[i]<<" 姓名 "<<name[i]<<" 分数 "<<x[i]<<"及格!"<<endl;
break;
case 5:
case 4:
case 3:
case 2:
case 1:
case 0: cout<<"学号 "<<num[i]<<" 姓名 "<<name[i]<<" 分数 "<<x[i]<<"不及格!"<<endl;
break;
}
}
cout<<endl;
}
float max(float x[],int n)
{
int i;
float max;
max=x[0];
for(i=1;i<n;i++)
{
if(max<=x[i])
max=x[i];
}
return max;
return max;
}
float mix(float x[],int n)
{
int i;
float mix;
mix=x[0];
for(i=1;i<n;i++)
{
if(mix>=x[i])
mix=x[i];
}
return mix;
}
float average(float x[],int n)
{
int i;
float sum=0;
for(i=0;i<n;i++)
{
sum+=x[i];
}
return (sum/n);
}
void caizao(float x[],int n,char num[][P],char name[][P])
{
int k;
char p='y';
cout<<endl;
cout<<"<<同学信息查找>>";
cout<<endl;
while(p!='N'&&p!='n')
{
cout<<endl;
cout<<"以学号形式输入（1）或以姓名形式输入（2）";
cin>>k;
switch(k)
{
case 1: yxhxs(n,x,num,name);
cout<<endl;
break;
case 2: yxmxs(n,x,num,name);
cout<<endl;
break;
}
cout<<endl;
cout<<"要继续进行同学信息查找输入任意键否则N或n";
cin>>p;
}
}
void yxhxs(int n,float x[],char num[][P],char name[][P])
{
char nu[P];
int i;
char s='y';
cout<<endl;
while(s!='N'&&s!='n')
{
cout<<"请输入学号 ";
cin>>nu;
cout<<endl;
for(i=0;i<n;i++)
{
if(strcmp(num[i],nu)==0)//用来判断两个字符串相等
{
cout<<"学号 "<<num[i]<<" 姓名 "<<name[i]<<" 分数 ";
cout<<x[i]<<" ";
}
}
cout<<endl;
cout<<"要继续进行学号形式查找学生信息按任意键否则输入N或n";
cin>>s;
}
cout<<endl;
}
void yxmxs(int n,float x[],char num[][P],char name[][P])
{
int i;
char na[P];
char s='y';
cout<<endl;
while(s!='N'&&s!='n')
{
cout<<endl;
cout<<"请输入姓名 ";
cin>>na;
for(i=0;i<n;i++)
{
if(strcmp(name[i],na)==0)//用来判断两个字符串相等
{
cout<<"学号 "<<num[i]<<" 姓名 "<<name[i]<<" 分数 ";
cout<<x[i]<<" ";
}
}
cout<<endl;
cout<<endl;
cout<<"要继续进行姓名形式查找学生信息按任意键否则输入N或n";
cin>>s;
}
cout<<endl;
}
void main()
{
int k;
cout<<"<<欢迎使用成绩处理程序!>> "<<endl;
cout<<"作者：罗振辉 "<<endl;
cout<<endl;
cout<<"单科处理（实用单个老师进行单科成绩处理）输入1"<<endl;
cout<<"全科成绩处理（实用大众,多科成绩处理）输入2"<<endl;
cout<<"请选择k=";
cin>>k;
switch(k)
{
case 1: mian();
break;
case 2: miin();
break;
}
cout<<endl;
}
//说明；接收回车键enter;
//说明输出一定要放在最后面
//注意；这里void中不一定要有输出结果
//再设定一个函数交换num[i+1]中的值；
//求最大值可设一个函数
//在这里如果输入多个数字时，可以考虑用二维数组（char）性使用
///字符串的复制利用
//if(strcmp(num[i],nu)==0)//用来判断两个字符串相等
//sum=0;//每次副初值为0；
//成绩评优问提
//注意long 的含义：：“：
//数量运算等级太差