问题描述

Linux 下编译C出错(windows编译正常)

Ubuntu 15
gcc version 5.2.1
错误：

scritpt.hpp下是一个 命名空间
namespace script{
....
int setData( PyObject * pObj, Vector4 & rVal, const char * varName = "" );
int setData( PyObject * pObj, Matrix & rVal, const char * varName = "" );
int setData( PyObject * pObj, PyObject * & rVal,
const char * varName = "" );
int setData( PyObject * pObj, SmartPointer & rPyObject,
const char * varName = "" );
int setData( PyObject * pObj, Capabilities & rCaps,
const char * varName = "" );
int setData( PyObject * pObj, std::string & rString,
const char * varName = "" );
int setData( PyObject * pObj, std::wstring & rString,
const char * varName = "" );
int setData( PyObject * pObj, char * & rString,
const char * varName = "" );
int setData( PyObject * pObj, Mercury::Address & rAddr,
const char * varName = "" );

template <class T>
PyObject * getReadOnlyData( const T & d )
{
    return getData( d ); //出问题的地方126行
}

PyObject * getData( const bool data );
PyObject * getData( const int data );
PyObject * getData( const uint data );
....

}

stl_to_py.cpp
PyObject * Script::getData( const PySTLSequenceHolderBase & holder ) //出错位置
{
return new PySTLSequence(
const_cast(holder), holder.pOwner() );
}

stl_to_py.hpp 中
namespace Script
{
int setData( PyObject * pObject, PySTLSequenceHolderBase & data,
const char * varName = "" );

PyObject * getData( const PySTLSequenceHolderBase & data );

};

不知道哪里出错了,求大神指点

是有定义了的
定义在st_to_py.hpp中
note:
stl_to_py.cpp:506 'PyObjest * Script::getData(const PySTLSequenceHoldBase &) ' declared here ,later in the translation unit
PyObjest * Script::getData(const PySTLSequenceHoldBase & holder)

st_to_py.hpp 是 include了 script.hpp

这个在window环境下是能编译通过的

解决方案

把声明放前面试试：

PyObject * getData( const bool data );
PyObject * getData( const int data );
PyObject * getData( const uint data );

 template <class T>
PyObject * getReadOnlyData( const T & d )
{
    return getData( d ); //出问题的地方126行
}

解决方案二：

从出错信息看：getData( d )未定义，检查一下看看吧，没看到定义部分。

解决方案三：

this->getData

解决方案四：

方法未声明，，，，，