问题描述

对同一个button生成不同的事件

如何对一个button定义两次事件，比如，单击时产生一个事件，然后双击时产生另一个不同的事件？请高手指教，谢谢！

解决方案

可以用条件句 setAction :

单击调用selectorSingleTouch.

其他调用selectorDoubleTouch.

//没有经过编译检测，只是给你个思路

UITapGestureRecognizer *singleTap=[[UITapGestureRecognizer alloc] initWithTarget: self action:@selector(doSingleTap)];singleTap.numberOfTapsRequired = 1; [self.view addGestureRecognizer:singleTap];UITapGestureRecognizer *doubleTap=[[UITapGestureRecognizer alloc] initWithTarget: self action:@selector(doDoubleTap)];doubleTap.numberOfTapsRequired = 2; [self.view addGestureRecognizer:doubleTap];

解决方案二：
设置初始button标签为0

然后：

-(IBAction)yourBtnPress:(id)sender{    UIButton *btn = (UIButton*)sender;    if (btn.tag==0)    {        btn.tag=1;        //singlePress    }    else if(btn.tag==1)    {        //double tap        //if you want other action then change tag        btn.tag=2;        //if you restart task then        btn.tag=0;    }    }

解决方案三：
我的方法可行：

其中tapCount是int变量，在 .h中声明

- (void)viewDidLoad{  tapCount = 0; // Count tap on Slider  UITapGestureRecognizer *gr = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(ButtonTap:)];    [button addGestureRecognizer:gr];} - (void)ButtonTap:(UIGestureRecognizer *)g     {/////////////// For TapCount////////////        tapCount = tapCount + 1;        NSLog(@""Tap Count -- %d""tapCount);/////////////// For TapCount////////////if (tapCount == 1){       // code for first tap}else if (tapCount == 2){      // Code for second tap}}