问题描述
gongsi(公司表)id:summary:artices(文章表)id:gongsi_id:content:公司排序(以文章总数进行降序排序)
解决方案
select G.id,G.summary,count(A.id) as c from gongsi as G join artices as A on A.gongsi_id = G.id order by c 你试试
解决方案二:
select id, summary from ( select G.id, G.summary, count(A.id) cnt from gongsi as G inner join artices as A on A.gongsi_id = G.id group by G.id ) t order by cnt desc
解决方案三:
select id, summaryfrom (select G.id, G.summary, count(A.id) cntfrom gongsi as G join artices as A on A.gongsi_id = G.idgroup by G.id) torder by cnt
时间: 2024-07-31 03:44:07