问题描述

cocos2d中关于回调函数的pSender参数的问题 10C

运行结果显示，CallBack1和CallBack2产生的效果是一样的，请问CallBack2处的pSender的作用是什么，为什么Sprite* sp = (Sprite*)pSender;后sp与sprite等效了？

cpp中

 void MyScene::goMenu(cocos2d::Ref* pSender){    log(""Tag=%i""this->getTag());    switch (this->getTag())    {    case func:        this->OnCallFunc(pSender);        break;    case funcN:        this->OnCallFuncN(pSender);        break;    }}void MyScene::backMenu(Ref* pSender){    Scene* scene = HelloWorld::createScene();    Director::getInstance()->replaceScene(scene);}void MyScene::OnCallFunc(Ref* pSender){    FiniteTimeAction* ac1 = MoveBy::create(2Vec2(100100));    FiniteTimeAction* ac2 = ac1->reverse();    FiniteTimeAction* acf = CallFunc::create(CC_CALLBACK_0(MyScene::CallBack1this));    FiniteTimeAction* seq = Sequence::create(ac1acfac2NULL);    log(""%p"" this->sprite);    this->sprite->runAction(Sequence::create(seqNULL));}void MyScene::OnCallFuncN(Ref* pSender){    FiniteTimeAction* ac1 = MoveBy::create(2 Vec2(100 100));    FiniteTimeAction* ac2 = ac1->reverse();    FiniteTimeAction* acf = CallFuncN::create(CC_CALLBACK_1(MyScene::CallBack2 this));    FiniteTimeAction* seq = Sequence::create(ac1 acf ac2 NULL);    sprite->runAction(Sequence::create(seqNULL));}void MyScene::CallBack1(){    sprite->runAction(TintBy::create(0.5 255 0 255));}void MyScene::CallBack2(Ref* pSender){    Sprite* sp = (Sprite*)pSender;    sp->runAction(TintBy::create(0.5 255 0 255));}

头文件中

 #pragma once#include ""cocos2d.h""using namespace cocos2d;class MyScene :public Layer{    Sprite* sprite;public:    static Scene* createScene();    virtual bool init();    CREATE_FUNC(MyScene);    void goMenu(Ref* pSender);    void backMenu(Ref* pSender);    void OnCallFunc(Ref* pSender);    void OnCallFuncN(Ref* pSender);    void CallBack1();    void CallBack2(Ref* pSender);};

解决方案

http://www.2cto.com/kf/201401/275831.html