问题描述

安卓中使用SQlite报错

创建一个数据库，根据返回值设置textView值。然后报错："SYNTAX ERROR(code1) "

代码：

package com.example.dbex;
import java.sql.SQLOutput;
import java.sql.SQLPermission;
import android.content.ContentValues;
import android.content.Context;
import android.database.Cursor;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteDatabase.CursorFactory;
import android.database.sqlite.SQLiteOpenHelper;

public class DBHandler extends SQLiteOpenHelper {
    public static final int DATABASE_VERSION=1;
    public static final String DATABASE_NAME="contactsmanager";
    public static final String TABLE_CONTACTS="contacts";
    public static final String KEY_ID="id";
    public static final String KEY_NAME="name";
    public static final String KEY_NUMBER="number";
    public DBHandler(Context context) {
        super(context,DATABASE_NAME, null, DATABASE_VERSION);
        // TODO Auto-generated constructor stub
    }
    @Override
    public void onCreate(SQLiteDatabase db) {
        // TODO Auto-generated method stub
        String CREATE_TABLE_CONTACTS="CREATE TABLE"+TABLE_CONTACTS+"("+KEY_ID+"INTEGER PRIMARY KEY,"+KEY_NAME+"TEXT,"+KEY_NUMBER+"TEXT"+")";
        db.execSQL(CREATE_TABLE_CONTACTS);
    }
    @Override
    public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
        // TODO Auto-generated method stub
        db.execSQL("DROP TABLE IF EXISTS"+TABLE_CONTACTS);
        onCreate(db);
    }
    public void addContact(Contacts contacts)
    {
        SQLiteDatabase db=this.getWritableDatabase();
        ContentValues values=new ContentValues();
        values.put(KEY_NAME, contacts.getname());
        values.put(KEY_NUMBER, contacts.getnumber());
        db.insert(TABLE_CONTACTS,null,values);
        db.close();
    }
    public Contacts getContact(int id)
    {
        SQLiteDatabase db=this.getReadableDatabase();
        Cursor c=db.query(TABLE_CONTACTS, new String[]{KEY_ID,KEY_NAME,KEY_NUMBER},KEY_ID+"=?",new String[]{String.valueOf(id)}, null, null, null, null);
        if(c!=null)
        {
            c.moveToFirst();
        }
        Contacts contacts=new Contacts(Integer.parseInt(c.getString(0)),c.getString(1),c.getString(2));
        return contacts;
    }
    public void deleteContact(Contacts contacts)
    {
        SQLiteDatabase db=this.getWritableDatabase();
        db.delete(TABLE_CONTACTS, KEY_ID+"=?", new String[]{String.valueOf(contacts.getID())});
        ``db.close();
    }
}