本文实例讲述了Yii实现单用户博客系统文章详情页插入评论表单的方法。分享给大家供大家参考,具体如下:
action部分:
<?php function test($objs) { $objs->var=10; } class one { public $var=1; } $obj=new one(); echo $obj->var.'<p>'; test($obj); echo $obj->var; exit;
PostController.php页面:
... /** * Displays a particular model. * @param integer $id the ID of the model to be displayed */ public function actionView($id) { $post=$this->loadModel($id); $comment=$this->newComment($post); $this->render('view',array( 'model'=>$post, 'comment'=>$comment, )); } protected function newComment($post) { $comment=new Comment(); if(isset($_POST['Comment'])) { $comment->attributes=$_POST['Comment']; if($post->addComment($comment))//============================== { if($comment->status==Comment::STATUS_PENDING) Yii::app()->user->setFlash('commentSubmitted','Thank you...'); $this->refresh(); } } return $comment; } ...
models/Post.php页面:
... public function addComment($comment) { if(Yii::app()->params['commentNeedApproval']) $comment->status=Comment::STATUS_PENDING; else $comment->status=Comment::STATUS_APPROVED; $comment->post_id=$this->id; return $comment->save(); } ...
post/view.php页面:
... <div id="comments"> <h3>Leave a Comment</h3> <?php if(Yii::app()->user->hasFlash('commentSubmitted')): ?> <div class="flash-success"> <?php echo Yii::app()->user->getFlash('commentSubmitted'); ?> </div> <?php else: ?> <?php $this->renderPartial('/comment/_form',array( 'model'=>$comment, )); ?> <?php endif; ?> </div><!-- comments --> ...
希望本文所述对大家基于Yii框架的PHP程序设计有所帮助。
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, 插入
, 文章详情页
, 评论表单
Yii评论表单
yii2 ajax 提交表单、yii2 表单、yii2 form表单提交、yii2 表单验证、yii2防止表单重复提交,以便于您获取更多的相关知识。
时间: 2024-08-02 09:12:05