问题描述

http post方法传递到服务器null值

         try          {            url= new URL(ConstantsClass.VENDOR_FOLLOW + ""?UID="" +android_id+""&URL='""+resultfinal+""'&device=android"");                connection = (HttpURLConnection) url.openConnection();                connection.setDoOutput(true);                connection.setRequestMethod(""POST"");                request = new OutputStreamWriter(connection.getOutputStream());                request.flush();                request.close();                request.write(""Hello!!!"");                String line = """";                InputStreamReader isr = new InputStreamReader(connection.getInputStream());                BufferedReader reader = new BufferedReader(isr);                StringBuffer sb = new StringBuffer();                while((line=reader.readLine())!=null) {                    sb.append(line + ""&"");                }                response = sb.toString();                //response.getEntity().getContent();                Log.i(""Test""updated response: "" + response);            }         catch (IOException e) {              e.printStackTrace();          }            Log.i(""Test""**************url list********************"" + url);         tag_text.setOnClickListener(new OnClickListener() {                public void onClick(View v) {                    // TODO Auto-generated method stub                    Intent in=new Intent(contextLinkWebView.class);                    in.putExtra(""vendorUrl"" resultfinal);                    context.startActivity(in);                          //postData();                }            });             }    tag_text.setTextSize(16);    return view;} 

我想把一个值从url中传递到服务中，但是在服务这边获得是null值。重新响应后server依然还是null值。我想传递代码中给出的url中的url、android_id和device。使用httpclient也还是返回的null值。谁知道怎么传递这个值呢？

解决方案

ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(); nameValuePairs.add(new BasicNameValuePair(""Your_var_1"" value)); nameValuePairs.add(new BasicNameValuePair(""Your_var_2"" value));

然后再创建你的web链接

try    {        HttpClient httpclient = new DefaultHttpClient();        HttpPost httppost = new HttpPost(""your url only ex:www.google.com/abc"");        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));        HttpParams httpParameters = new BasicHttpParams();        DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);        HttpResponse response = httpclient.execute(httppost);        HttpEntity entity = response.getEntity();        is = entity.getContent();    } catch (Exception e)     {           Log.e(""Loading Runnable Error in http connection  :"" e.toString());    }

现在检索响应流

try     {        BufferedReader reader = new BufferedReader(new InputStreamReader(isiso-8859-1"") 8);        StringBuilder sb = new StringBuilder();        String line = null;        while ((line = reader.readLine()) != null)         {            sb.append(line + ""n"");        }        is.close();        result = sb.toString();    }    catch (Exception e)     {           Log.e(""Loading Runnable Error converting result :"" e.toString());    }

现在在最终的结果中包含整个输出字符串，就取决于你如何读取数据。我使用json示例代码希望能帮得上你啊。

JSONObject json_data = new JSONObject(result);// its a string var which contain output.         my_output_one = json_data.getString(""var_1""); // its your response var form web.        my_output_two = json_data.getString(""var_2"");

解决方案二：
代码贴出来 估计你在处理数据的时候没装进去 你这样说很难知道为什么

解决方案三：
有代码才能知道你写的哪里有问题啊。不然说的很空洞，不能详细。