问题描述

改写代码：请问下面的代码 怎么用循环或者遍历的方式改写呀

public TodayExamWidget() {
    self = binder.createAndBindUi(this);

    int row  =1 ;
    gridWidget = new Grid();
    gridWidget.resize(row,3);
    gridWidget.setSize("100","100");
    gridWidget.setText(0,0,"Uncorrected");
    gridWidget.addStyleName("gray_cell");
    gridWidget.setBorderWidth(1);
    gridWidget.getCellFormatter().setWidth(0,0,"160");
    gridWidget.getCellFormatter().setWidth(0,1,"60");
    gridWidget.getCellFormatter().setWidth(0,2,"60");

    visionFlowPanel.add(gridWidget);
}

    private void populateVisualAcuity(Grid gridWidget, VisualAcuityCollection visualAcuityCollection) {
    int rowCount = gridWidget.getRowCount();
    if(!visualAcuityCollection.normal.isEmpty()){

        gridWidget.resize(rowCount +1,3);
        gridWidget.setText(rowCount -2,0,VisualAcuityType.NORMAL.toString());
        gridWidget.setText(rowCount -2,1,visualAcuityCollection.normal.od.distance);
        gridWidget.setText(rowCount -2,2,visualAcuityCollection.normal.os.distance);
    }
    if(!visualAcuityCollection.pinhole.isEmpty()){
        gridWidget.resize(rowCount +1,3);
        gridWidget.setText(rowCount -2,0,VisualAcuityType.PINHOLE.toString());
        gridWidget.setText(rowCount -2,1,visualAcuityCollection.pinhole.od.distance);
        gridWidget.setText(rowCount -2,2,visualAcuityCollection.pinhole.os.distance);
    }
    if(!visualAcuityCollection.binocular.isEmpty()){
        gridWidget.resize(rowCount +1,3);
        gridWidget.setText(rowCount -2,0,VisualAcuityType.BINOCULAR.toString());
        gridWidget.setText(rowCount -2,1,visualAcuityCollection.binocular.od.distance);
        gridWidget.setText(rowCount -2,2,visualAcuityCollection.binocular.os.distance);
    }

    row = rowCount;
}

    主要是上面的那个popluteVisualVison 方法， 又没有什么方法让代码 用loop形式改写？ 谢谢啦 各位大神门

解决方案

Java下的Lambda好丑陋。

解决方案二：

能否循环，则要看 visualAcuityCollection.normal、visualAcuityCollection.pinhole 和 visualAcuityCollection.binocular 是否是相同的类型？
如果是，则可以考虑用一个变量来代替它们实现循环。循环内的代码也不一样，看看有没有什么规律吧，如： VisualAcuityType。

解决方案三：

用lambda表达式可以做到
Function [] funcs = new Function<>[]{visualAcuityCollection.normal::isEmpty, visualAcuityCollection.pinhole::isEmpty, visualAcuityCollection.binacular::isEmpty};

for(Function func : funs) {
....
}