问题描述

如何格式化字符串变量的数据？

在NSString存日期：

1900-01-01T11:00:00

需要进行格式化，然后加了一个格式器：

NSDateFormatter *df = [[NSDateFormatter alloc] init];
    [df setDateFormat:@"dd/MM/yyyy hh:mm:ss a"];

如何进行格式化？

NSString* formatedDateString = [df ???];

解决方案

你要创建两个日期格式器。一个用于解析，一个用于格式化~

NSString * targetString = @"1900-01-01'T'11:00:00";

NSDateFormatter *parseFormat = [[NSDateFormatter alloc] init];
[parseFormat setDateFormat:@"yyyy-MM-ddThh:mm:ss"];
NSDate * date = [parseFormat dateFromString:targetString];

NSDateFormatter * outputFormat = [[NSDateFormatter alloc] init];
[outputFormat setDateFormat:@"dd/MM/yyyy hh:mm:ss a";
NSString * outputString = [parseFormat stringFromDate:date];

解决方案二：

NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateStyle:NSDateFormatterMediumStyle];
[dateFormatter setTimeStyle:NSDateFormatterNoStyle];

NSDate *date = [NSDate dateWithTimeIntervalSinceReferenceDate:162000];

NSString *formattedDateString = [dateFormatter stringFromDate:date];
NSLog(@"formattedDateString: %@", formattedDateString);
// Output for locale en_US: "formattedDateString: Jan 2, 2001".

解决方案三：

NSString * targetString = @"1900-01-01'T'11:00:00";

NSDateFormatter *parseFormat = [[NSDateFormatter alloc] init];
[parseFormat setDateFormat:@"yyyy-MM-ddThh:mm:ss"];
NSDate * date = [parseFormat dateFromString:targetString];

NSDateFormatter * outputFormat = [[NSDateFormatter alloc] init];
[outputFormat setDateFormat:@"dd/MM/yyyy hh:mm:ss a";
NSString * outputString = [parseFormat stringFromDate:date];