第九周-任务1-Complex类中运算符的重载

【题目】接第8周任务1,定义Complex类中的<<和>>运算符的重载,实现输入和输出,改造原程序中对运算结果显示方式,使程序读起来更自然。

【参考解答】

#include <iostream>
using namespace std;
class Complex
{
public:
	Complex(){real=0;imag=0;}
	Complex(double r,double i){real=r;imag=i;}
	Complex operator-();
	//实现输入、输出的运算符重载
	friend ostream& operator << (ostream& output,Complex& c);
	friend istream& operator >> (istream& input,Complex& c);
	//实现加减乘除的运算符重载
	friend Complex operator+(Complex &c1, Complex &c2);
	friend Complex operator+(double d1, Complex &c2);
	friend Complex operator+(Complex &c1, double d2);
	friend Complex operator-(Complex &c1, Complex &c2);
	friend Complex operator-(double d1, Complex &c2);
	friend Complex operator-(Complex &c1, double d2);
	friend Complex operator*(Complex &c1, Complex &c2);
	friend Complex operator*(double d1, Complex &c2);
	friend Complex operator*(Complex &c1, double d2);
	friend Complex operator/(Complex &c1, Complex &c2);
	friend Complex operator/(double d1, Complex &c2);
	friend Complex operator/(Complex &c1, double d2);
private:
	double real;
	double imag;
};

//实现输出的运算符重载
ostream& operator << (ostream& output,Complex& c)
{	output<<"("<<c.real;
	if(c.imag>=0) output<<"+";
	output<<c.imag<<"i)";
	return output;
}

//实现输入的运算符重载
istream& operator >> (istream& input,Complex& c)
{	int a,b;
	char sign,i;
	do
	{	cout<<"input a complex number(a+bi或a-bi):";
		input>>a>>sign>>b>>i;
	}
	while(!((sign=='+'||sign=='-')&&i=='i'));
	c.real=a;
	c.imag=(sign=='+')?b:-b;
	return input;
}

Complex Complex::operator-()
{
	return(0-*this);
}

//复数相加:(a+bi)+(c+di)=(a+c)+(b+d)i.
Complex operator+(Complex &c1, Complex &c2)
{
	Complex c;
	c.real=c1.real+c2.real;
	c.imag=c1.imag+c2.imag;
	return c;
}
Complex operator+(double d1, Complex &c2)
{
	Complex c(d1,0);
	return c+c2; //按运算法则计算的确可以,但充分利用已经定义好的代码,既省人力,也避免引入新的错误,但可能机器的效率会不佳
}
Complex operator+(Complex &c1, double d2)
{
	Complex c(d2,0);
	return c1+c;
}
//复数相减:(a+bi)-(c+di)=(a-c)+(b-d)i.
Complex operator-(Complex &c1, Complex &c2)
{
	Complex c;
	c.real=c1.real-c2.real;
	c.imag=c1.imag-c2.imag;
	return c;
}
Complex operator-(double d1, Complex &c2)
{
	Complex c(d1,0);
	return c-c2;
}
Complex operator-(Complex &c1, double d2)
{
	Complex c(d2,0);
	return c1-c;
}

//复数相乘:(a+bi)(c+di)=(ac-bd)+(bc+ad)i.
Complex operator*(Complex &c1, Complex &c2)
{
	Complex c;
	c.real=c1.real*c2.real-c1.imag*c2.imag;
	c.imag=c1.imag*c2.real+c1.real*c2.imag;
	return c;
}
Complex operator*(double d1, Complex &c2)
{
	Complex c(d1,0);
	return c*c2;
}
Complex operator*(Complex &c1, double d2)
{
	Complex c(d2,0);
	return c1*c;
}

//复数相除:(a+bi)/(c+di)=(ac+bd)/(c^2+d^2) +(bc-ad)/(c^2+d^2)i
Complex operator/(Complex &c1, Complex &c2)
{
	Complex c;
	c.real=(c1.real*c2.real+c1.imag*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);
	c.imag=(c1.imag*c2.real-c1.real*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);
	return c;
}
Complex operator/(double d1, Complex &c2)
{
	Complex c(d1,0);
	return c/c2;
}

Complex operator/(Complex &c1, double d2)
{
	Complex c(d2,0);
	return c1/c;
}

int main()
{
	Complex c1,c2,c3;
	double d=11;
	cout<<"c1: "<<endl;;
	cin>>c1;
	cout<<"c2: "<<endl;
	cin>>c2;
	cout<<"c1="<<c1<<endl;
	cout<<"c2="<<c2<<endl;
	cout<<"d="<<d<<endl;
	cout<<"-c1="<<(-c1);
	c3=c1+c2;
	cout<<"c1+c2="<<c3<<endl;
	cout<<"c1+d="<<(c1+d)<<endl;
	cout<<"d+c1="<<(d+c1)<<endl;
	c3=c1-c2;
	cout<<"c1-c2="<<c3<<endl;
	cout<<"c1-d="<<(c1-d)<<endl;
	cout<<"d-c1="<<(d-c1)<<endl;
	c3=c1*c2;
	cout<<"c1*c2="<<c3<<endl;
	cout<<"c1*d="<<(c1*d)<<endl;
	cout<<"d*c1="<<(d*c1)<<endl;
	c3=c1/c2;
	cout<<"c1/c2="<<c3<<endl;
	cout<<"c1/d="<<(c1/d)<<endl;
	cout<<"d/c1="<<(d/c1)<<endl;

	system("pause");
	return 0;
}
时间: 2024-12-17 10:58:43

第九周-任务1-Complex类中运算符的重载的相关文章

第9周-任务3-分数类中运算符重载

[题目]接第8周任务3,定义分数类中<<和>>运算符重载,实现时间的输入输出,改造原程序中对运算结果显示方式,使程序读起来更自然. [参考解答] #include <iostream> using namespace std; class CFraction { private: int nume; // 分子 int deno; // 分母 public: CFraction(int nu=0,int de=1):nume(nu),deno(de){} void si

第8周-任务1-方案2-复数类中运算符重载(非成员函数实现)

接:第8周-任务1-方案1-复数类中运算符重载(成员函数实现) 本文用方案二求解:用类的友元函数,而不是成员函数,完成上面提及的运算符的重载: [讲解视频] [参考解答] #include <iostream> using namespace std; class Complex { public: Complex(){real=0;imag=0;} Complex(double r,double i){real=r;imag=i;} friend Complex operator+(Comp

第8周-任务1-方案3-复数类中运算符重载(与实数运算)

接:第8周-任务1-方案2-复数类中运算符重载(非成员函数实现) 本文在方案2的基础上,扩展+.-.*./运算符的功能,使之能与double型数据进行运算.设Complex c; double d; c?d和d?c的结果为"将d视为实部为d的复数同c运算"的结果(其中?为+.-.*./之一).另外,再定义一目运算符 -,-c相当于0-c. [讲解视频] [参考解答] 在下面的解答中,我将所有二目运算符的重载定义为友元函数,一目运算符重载为成员函数,这是惯用的做法. #include &

C++第8周项目3 - 分数类中的运算符重载

课程首页地址:http://blog.csdn.net/sxhelijian/article/details/7910565,本周题目链接:http://blog.csdn.net/sxhelijian/article/details/8806111 [项目3-分数类中的运算符重载]实现分数类中的运算符重载,在分数类中可以完成分数的加减乘除(运算后再化简).求反.比较(6种关系)的运算.可以从第5周项目2的代码开始工作. class CFraction {private: int nume; /

第9周-任务2-Time类中运算符重载

[题目]接第8周任务2,定义Time类中的<<和>>运算符重载,实现时间的输入输出,改造原程序中对运算结果显示方式,使程序读起来更自然. [参考解答] #include <iostream> using namespace std; class CTime { private: unsigned short int hour; // 时 unsigned short int minute; // 分 unsigned short int second; // 秒 pub

C++第7周项目5 - 模板类中使用友元函数

课程首页地址:http://blog.csdn.net/sxhelijian/article/details/7910565,本周题目链接:http://blog.csdn.net/sxhelijian/article/details/8775137 [项目5-模板类中使用友元函数]友元函数提供了一种非成员函数访问私有数据成员的途径,模板类使类中的数据成员的类型变得灵活,这两种技术可以结合起来用.要求在项目4的基础上能够支持用友员函数实现的加法.用于测试的main()函数如下: int main

字符串类中运算符重载出现的一个问题

上机辅导.学生的一个程序莫名出问题.她是在做一个String类,主要是要实现字符串的连接. 程序是这样的,请读者将其拷到IDE,边看边调: #include <iostream> #include <cassert> #include <cstring> using namespace std; class String { private: char* p; int len; public: String(); String(const char* s); Strin

C++第9周项目1 - 实现复数类中的运算符重载

课程首页地址:http://blog.csdn.net/sxhelijian/article/details/7910565,本周题目链接:http://blog.csdn.net/sxhelijian/article/details/8841620 [项目1-Complex类]接第8周项目1,定义Complex类中的<<和>>运算符的重载,实现输入和输出,改造原程序中对运算结果显示方式,使程序读起来更自然. 参考解答:(在VS2008中调试通过,CodeBlocks中有编译错误,

《C++语言基础》实践参考——复数类中的运算符重载(续)

返回:贺老师课程教学链接 项目要求 [项目1-复数类中的运算符重载(续)]在复数类中的运算符重载基础上(1)再定义一目运算符 -,-c相当于0-c.(2)定义Complex类中的<<和>>运算符的重载,实现输入和输出,改造原程序中对运算结果显示方式,使程序读起来更自然.[参考解答] #include <iostream> using namespace std; class Complex { public: Complex() { real=0; imag=0; }