问题描述

3x3的二维矩阵里面随机的用0或1填充，找出该矩阵里面的相同行或者列，没有输出

package exercise_7;

public class Exercise7_10 {

public static void main(String[] args) {

    int[][] test = new int[3][3];
    for (int i = 0; i < test.length; i++) {
        for (int j = 0; j < test[i].length; j++) {
            int t = (int) (Math.random() * 2);
            test[i][j]=t;
            System.out.print(test[i][j]+ " ");
        }
        System.out.println();
    }//自动生成一个3—3的数组

    boolean flag=true;
for (int i = 0; i < test.length; i++) {
    flag=true;
    for (int j = 0; j < test[i].length-1; j++) {//判断相同行
        if (test[i][j]!=test[i][j+1]) {
            flag=false;
            if (flag) {
                System.out.println("All is on row "+i);
                break;
            }
        }
    }
    for (int j = 0; j < test[i].length-1; j++) {//判断相同列
        if (test[j][i]!=test[j+1][i]) {
            flag=false;
            if (flag) {
                System.out.println("All is on column "+j);
                break;
            }
        }
    }
}

}

}

解决方案

package exercise_7;

public class Exercise7_10 {

public static void main(String[] args) {

    int[][] test = new int[3][3];
    for (int i = 0; i < test.length; i++) {
        for (int j = 0; j < test[i].length; j++) {
            int t = (int) (Math.random() * 2);
            test[i][j] = t;
            System.out.print(test[i][j] + " ");
        }
        System.out.println();
    }// 自动生成一个3—3的数组

    boolean flag = true;
    for (int i = 0; i < test.length; i++) {
        flag = true;
        for (int j = 0; j < test[i].length - 1; j++) {// 判断相同行
            if (test[i][j] != test[i][j + 1]) {
                flag = false;

            }
            if (flag) {
                System.out.println("All is on row " + i);
                break;
            }
        }
        for (int j = 0; j < test[i].length - 1; j++) {// 判断相同列
            if (test[j][i] != test[j + 1][i]) {
                flag = false;

            }
            if (flag) {
                System.out.println("All is on column " + j);
                break;
            }
        }
    }

}

}