问题描述

java新手，想问问有没有大牛给我解释一下这段代码，就是关于http报文传输的

需要添加httpmime包

这个是发post的method：
public static String sendPostRequest(String url, List nameValuePairs) {
// add code to validate required fields

    String res = null;

    try {
        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost(url);
        if (ListUtils.isNotEmpty(nameValuePairs)) {
            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
        }
        HttpResponse response = httpclient.execute(httppost);
        res = getResponseText(response);

        // add code check respond status

    } catch (ClientProtocolException e) {
        if (listener != null) {
            listener.onError(null);
        }
        CLog.e(HttpUtils.class, e.getMessage() + "");
    } catch (IOException e) {
        if (listener != null) {
            listener.onError(null);
        }
        CLog.e(HttpUtils.class, e.getMessage() + "");
    } catch (IllegalStateException e) {
        CLog.e(HttpUtils.class, e.getMessage());
        if (listener != null) {
            listener.onError(null);
        }
    }
    return res;
}

调用example：
List params = new LinkedList();

params.add(new BasicNameValuePair("pid", Integer.toString(pid)));

params.add(new BasicNameValuePair("comment", comment));

HttpUtils.sendPostRequest(“http://192.168.1.1/test.php”, params);

解决方案

你最好先去了解一下http的请求方式，和请求步骤，在对着代码，查查API就能看懂了

解决方案二：

这有什么好解释的？

HttpPost httppost = new HttpPost(url);
用 url 新建一个 HTTP POST 的request

httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
添加 parmaters

HttpResponse response = httpclient.execute(httppost);
执行 HTTP POST 并得到 response

res = getResponseText(response);
把response 换成 可以阅读的 TEXT

其实在 response 里关键是要检查 status 是不是 200， 400， 500 等等