问题描述
- 急!ssh项目出错Error setting value [[Ljava.lang.String;@1597a48]
-
spring:4.1.5
struts2:2.3.20
hibernate:4.3.8
spring和struts已配置验证码的action
Tomcat启动后没错误,进入到注册页面也没错误,点四位验证码更换时(如图)
myeclipse的Console报如下错误:WARN OgnlValueStack:68 - Error setting value [[Ljava.lang.String;@1597a48] with expression [1429250952505]
java.lang.NumberFormatException: For input string: "1429250952505"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Integer.parseInt(Integer.java:495)
at java.lang.Integer.valueOf(Integer.java:556)
at ognl.OgnlParserTokenManager.makeInt(OgnlParserTokenManager.java:63)
at ognl.OgnlParserTokenManager.TokenLexicalActions(OgnlParserTokenManager.java:1624)
at ognl.OgnlParserTokenManager.getNextToken(OgnlParserTokenManager.java:1498)
at ognl.OgnlParser.jj_ntk(OgnlParser.java:3099)......
注册页面jsp:
<tr> <th> <span class="requiredField">*</span>验证码: </th> <td> <span class="fieldSet"> <input type="text" id="checkcode" name="checkcode" class="text captcha" maxlength="4" autocomplete="off"/> <img id="checkImage" class="captchaImage" src="${pageContext.request.contextPath}/checkImage.action" onclick="changeImage()" title="点击更换验证码"/> </span> </td> </tr>
切换验证码的js代码:
function changeImage(){ var img = document.getElementById("checkImage"); img.src="${pageContext.request.contextPath}/checkImage.action?" + new Date().getTime(); }
action代码:
import java.awt.Color; import java.awt.Font; import java.awt.Graphics; import java.awt.Graphics2D; import java.awt.image.BufferedImage; import java.util.Random; import javax.imageio.ImageIO; import org.apache.struts2.ServletActionContext; import com.opensymphony.xwork2.ActionSupport; /** * 验证码Action类 * @author donny * @E-mail donnymoving@gmail.com * @version 2015-4-17 上午12:04:16 */ public class CheckImageAction extends ActionSupport { @Override public String execute() throws Exception { int width = 120; int height = 30; // 步骤一 绘制一张内存中图片 BufferedImage bufferedImage = new BufferedImage(width, height, BufferedImage.TYPE_INT_RGB); // 步骤二 图片绘制背景颜色 ---通过绘图对象 Graphics graphics = bufferedImage.getGraphics();// 得到画图对象 --- 画笔 // 绘制任何图形之前 都必须指定一个颜色 graphics.setColor(getRandColor(200, 250)); graphics.fillRect(0, 0, width, height); // 步骤三 绘制边框 graphics.setColor(Color.WHITE); graphics.drawRect(0, 0, width - 1, height - 1); // 步骤四 四个随机数字 Graphics2D graphics2d = (Graphics2D) graphics; // 设置输出字体 graphics2d.setFont(new Font("宋体", Font.BOLD, 18)); String words ="ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz1234567890"; Random random = new Random();// 生成随机数 // 定义StringBuffer StringBuffer sb = new StringBuffer(); // 定义x坐标 int x = 10; for (int i = 0; i < 4; i++) { // 随机颜色 graphics2d.setColor(new Color(20 + random.nextInt(110), 20 + random .nextInt(110), 20 + random.nextInt(110))); // 旋转 -30 --- 30度 int jiaodu = random.nextInt(60) - 30; // 换算弧度 double theta = jiaodu * Math.PI / 180; // 生成一个随机数字 int index = random.nextInt(words.length()); // 生成随机数 0 到 length - 1 // 获得字母数字 char c = words.charAt(index); sb.append(c); // 将c 输出到图片 graphics2d.rotate(theta, x, 20); graphics2d.drawString(String.valueOf(c), x, 20); graphics2d.rotate(-theta, x, 20); x += 30; } // 将生成的字母存入到session中 ServletActionContext.getRequest().getSession().setAttribute("checkcode", sb.toString()); // 步骤五 绘制干扰线 graphics.setColor(getRandColor(160, 200)); int x1; int x2; int y1; int y2; for (int i = 0; i < 30; i++) { x1 = random.nextInt(width); x2 = random.nextInt(12); y1 = random.nextInt(height); y2 = random.nextInt(12); graphics.drawLine(x1, y1, x1 + x2, x2 + y2); } // 将上面图片输出到浏览器 ImageIO graphics.dispose();// 释放资源 ImageIO.write(bufferedImage, "jpg", ServletActionContext.getResponse() .getOutputStream()); return NONE; } /** * 取其某一范围的color * * @param fc * int 范围参数1 * @param bc * int 范围参数2 * @return Color */ private Color getRandColor(int fc, int bc) { // 取其随机颜色 Random random = new Random(); if (fc > 255) { fc = 255; } if (bc > 255) { bc = 255; } int r = fc + random.nextInt(bc - fc); int g = fc + random.nextInt(bc - fc); int b = fc + random.nextInt(bc - fc); return new Color(r, g, b); } }
解决方案
话说,应该是数据类型转换不成功
解决方案二:
注册页面提交到
生成四位验证码的action:
public class CheckImageAction extends ActionSupport {
@Override
public String execute() throws Exception {
int width = 120;
int height = 30;
// 步骤一 绘制一张内存中图片
BufferedImage bufferedImage = new BufferedImage(width, height,
BufferedImage.TYPE_INT_RGB);
// 步骤二 图片绘制背景颜色 ---通过绘图对象
Graphics graphics = bufferedImage.getGraphics();// 得到画图对象 --- 画笔
// 绘制任何图形之前 都必须指定一个颜色
graphics.setColor(getRandColor(200, 250));
graphics.fillRect(0, 0, width, height);
// 步骤三 绘制边框
graphics.setColor(Color.WHITE);
graphics.drawRect(0, 0, width - 1, height - 1);
// 步骤四 四个随机数字
Graphics2D graphics2d = (Graphics2D) graphics;
// 设置输出字体
graphics2d.setFont(new Font("宋体", Font.BOLD, 18));
String words ="ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz1234567890";
Random random = new Random();// 生成随机数
// 定义StringBuffer
StringBuffer sb = new StringBuffer();
// 定义x坐标
int x = 10;
for (int i = 0; i < 4; i++) {
// 随机颜色
graphics2d.setColor(new Color(20 + random.nextInt(110), 20 + random
.nextInt(110), 20 + random.nextInt(110)));
// 旋转 -30 --- 30度
int jiaodu = random.nextInt(60) - 30;
// 换算弧度
double theta = jiaodu * Math.PI / 180;
// 生成一个随机数字
int index = random.nextInt(words.length()); // 生成随机数 0 到 length - 1
// 获得字母数字
char c = words.charAt(index);
sb.append(c);
// 将c 输出到图片
graphics2d.rotate(theta, x, 20);
graphics2d.drawString(String.valueOf(c), x, 20);
graphics2d.rotate(-theta, x, 20);
x += 30;
}
// 将生成的字母存入到session中
ServletActionContext.getRequest().getSession().setAttribute("checkcode", sb.toString());
// 步骤五 绘制干扰线
graphics.setColor(getRandColor(160, 200));
int x1;
int x2;
int y1;
int y2;
for (int i = 0; i < 30; i++) {
x1 = random.nextInt(width);
x2 = random.nextInt(12);
y1 = random.nextInt(height);
y2 = random.nextInt(12);
graphics.drawLine(x1, y1, x1 + x2, x2 + y2);
}
// 将上面图片输出到浏览器 ImageIO
graphics.dispose();// 释放资源
ImageIO.write(bufferedImage, "jpg", ServletActionContext.getResponse()
.getOutputStream());
return NONE;
}
/**
* 取其某一范围的color
*
* @param fc
* int 范围参数1
* @param bc
* int 范围参数2
* @return Color
*/
private Color getRandColor(int fc, int bc) {
// 取其随机颜色
Random random = new Random();
if (fc > 255) {
fc = 255;
}
if (bc > 255) {
bc = 255;
}
int r = fc + random.nextInt(bc - fc);
int g = fc + random.nextInt(bc - fc);
int b = fc + random.nextInt(bc - fc);
return new Color(r, g, b);
}
}
解决方案三:
关键错误信息在前两三行
解决方案四:
怎么感觉你点击刷新图片的时候,进入的Action方法,跳转返回的路径跳转错了?这个应该用Ajax吧
解决方案五:
execute() 你的这个方法有返回值,你看下你的这个返回值关联的是哪个页面