问题描述
NBX_211.94.128.22_aaa#eeee_211.138.45.11_sss#ggg_211.138.45.11_www#rrr需要截取aaa和eee要怎么截取?或者sss和ggg
解决方案
解决方案二:
Strings="NBX_211.94.128.22_aaa#eeee";Patternp=Pattern.compile(".*_.+_([a-z]+)#([a-z]+)");Matcherm=p.matcher(s);if(m.matches()){System.out.println(m.group(1)+","+m.group(2));}
解决方案三:
publicstaticvoidmain(String[]args){Stringstr="NBX_211.94.128.22_aaa#eeee";Stringa=str.substring(18,21);Stringe=str.substring(22,26);System.out.println(a);System.out.println(e);}
解决方案四:
用正则表达式,2楼正解
时间: 2024-08-30 07:57:08