问题描述

关于实参与形参类型不一致问题求解

#include<stdio.h>
#include<math.h>
double e(double *u,double *v)
{
    *u=exp(*u)*cos(*v);
    *v=exp(*u)*sin(*v);
    return ;
}

double ln(double *u,double *v)
{
    *u=ln(sqrt((*u)*(*u)+(*v)*(*v)));
    *v=atan((*v)/(*u));
    return;
}

double sin(double *u,double *v)
{
    *u=sin(*u)*(exp(*v)+exp(-(*v)))/2;
    *v=cos(*u)*(exp(*v)-exp(-(*v)))/2;
    return;
}

double cos(double *u,double *v)
{
    *u=cos(*u)*(exp(*v)+exp(-(*v)))/2;
    *v=-sin(*u)*(exp(*v)-exp(-(*v)))/2;
    return;
}

main()
{
    double x,y,a,b;
    double e(double *,double *);
    double ln(double *,double *);
    double sin(double *,double *);
    double cos(double *,double *);
    printf("请输入复数的实部和虚部x,y：");
    scanf("%lf%lf",&x,&y);
    a=x;b=y;
    e(&x,&y);
    printf("exp(%f+%fi)=%f+%fin",a,b,x,y);
    x=a;y=b;
    ln(&x,&y);
    printf("ln(%f+%fi)=%f+%fin",a,b,x,y);
    x=a;y=b;
    sin(&x,&y);
    printf("sin(%f+%fi)=%f+%fin",a,b,x,y);
    x=a;y=b;
    cos(&x,&y);
    printf("cos(%f+%fi)=%f+%fin",a,b,x,y);
}

问题如下：
1，错误 16 error C2198: “cos”: 用于调用的参数太少
2，错误 2 error C2440: “函数”: 无法从“double”转换为“double *”
（ 21 IntelliSense: "double" 类型的实参与 "double *" 类型的形参不兼容 ）
3， 警告 13 warning C4029: 声明的形参表不同于定义

4，警告 1 warning C4033: “e”必须返回值

不明白这是为什么，希望高手指点。

解决方案

 #include<stdio.h>
#include<math.h>
void e(double *u,double *v)//修改
{
    *u=exp(*u)*cos(*v);
    *v=exp(*u)*sin(*v);
}

void ln(double *u,double *v)//修改
{
    *u=log(sqrt((*u)*(*u)+(*v)*(*v)));//修改
    *v=atan((*v)/(*u));
}

void sin(double *u,double *v)//修改
{
    *u=sin(*u)*(exp(*v)+exp(-(*v)))/2;
    *v=cos(*u)*(exp(*v)-exp(-(*v)))/2;
}

void cos(double *u,double *v)//修改
{
    *u=cos(*u)*(exp(*v)+exp(-(*v)))/2;
    *v=-sin(*u)*(exp(*v)-exp(-(*v)))/2;
}

void main()
{
    double x,y,a,b;

    printf("请输入复数的实部和虚部x,y：");
    scanf("%lf%lf",&x,&y);
    a=x;b=y;
    e(&x,&y);
    printf("exp(%lf+%lfi)=%lf+%ln",a,b,x,y);//修改
    x=a;y=b;
    ln(&x,&y);
    printf("ln(%lf+%lfi)=%l+%lfin",a,b,x,y);//修改
    x=a;y=b;
    sin(&x,&y);
    printf("sin(%lf+%lfi)=%lf+%lfin",a,b,x,y);//修改
    x=a;y=b;
    cos(&x,&y);
    printf("cos(%lf+%lfi)=%lf+%lfin",a,b,x,y);//修改
}