问题描述
- hdu1003 主要是java中的printf和print
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package hdu; import java.math.BigInteger; import java.util.Scanner; public class hdu1003 { public static void main(String[] args){ Scanner cin=new Scanner(System.in); int n=cin.nextInt(); for(int i=1;i<=n;i++){ BigInteger a=cin.nextBigInteger(); BigInteger b=cin.nextBigInteger(); BigInteger c=a.add(b); System.out.println("Case"+" "+i+":"); System.out.println(a+" + "+b+" = "+c); /* *System.out.printf("Case %d:n",i); *System.out.printf("%d + %d = %dn",a,b,c); *这种提交结果是presentation error 为什么呢? *我在加号和等号两边也加了一个空格的啊 */ if(i<n) System.out.println(); } cin.close(); } }
题目是:
就是两个大数相加
Problem Description
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.Sample Input
2
1 2
112233445566778899 998877665544332211Sample Output
Case 1:
1 + 2 = 3Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110
解决方案
题意没有描述清楚,不知道你到底表达什么意思,是有报错吗?