面试题：整数取反

今天做了下英雄会在在线挑战，题目是

完成函数reverse，要求实现把给定的一个整数取其相反数的功能，举两个例子如下：

1. x = 123, return 321
2. x = -123, return -321

地址是http://hero.pongo.cn/Question/Details?ID=50&ExamID=48

我提交的代码是

// reverseIntergerTest.cpp : 定义控制台应用程序的入口点。
//

#include "stdafx.h"
#include<cstdio>
#include<iostream>
using namespace std;

int reverse(int x)
{

	int remainder;
	//旋转后的数
	int result = 0;
	bool negative = false;

	//要旋转的数是负数，则记录,并改为正数
	if(x < 0)
	{
		x = -x;
		negative = true;
	}

	while(x != 0)
	{
		remainder = x%10;
		x = x/10;
		result = result * 10 + remainder;
	}

	if(negative == true)
	    result = - result;

	return result;
}
int _tmain(int argc, _TCHAR* argv[])
{
	int number1 = 123;
	int number2 = -123;
	int result1 = reverse(number1);
	int result2 = reverse(number2);

	cout<<"Orignal number"<<number1<<"		After reverse:"<<result1<<endl;
	cout<<"Orignal number"<<number2<<"		After reverse:"<<result2<<endl;
	return 0;
}

感觉很初级呢