问题描述

新手C语言问题，求指教

要求编一个strcpy函数的原型 我大概写了一下 可是跟预期不一样 有没有人愿意指点一下

解决方案

字符串数组先用“”初始化一下，然后fuzhi函数最后加一个'',源码在下面，顺便把比较也实现给你好了，
#include "stdio.h"
#include "iostream"
#include
using namespace std;

void fuzhi(const char* src, char* des)
{
int i = 0;
for (; src[i] != ''; i++)
{
des[i] = src[i];
}
des[i + 1] = '';
}

int bijiao(char* src, char* des)
{
int i = 0;
while (true)
{
if (src[i] == '' || des[i] == '')
{
if (src[i] == '' && des[i] == '')
{
return 0;
}
else
{
if (src[i] == '' && des[i] != '')
return -1;
else
return 1;
}

    }
    int iState = int(src[i]) == int(des[i]);
    if (iState == 1)
    {
        iState = 0;
    }
    else
    {
        iState = int(src[i]) - int(des[i]);
    }
    if (iState  != 0)
    {
        return iState;
    }
    i++;
}

}
void main()
{
char src[256] = "I am src string";
char des[255] = "";
fuzhi(src, des);
cout << src << endl;
cout << des << endl;
cout << bijiao(src, des) << endl;
strcpy_s(des, src);
cout << bijiao(src, des) << endl;
system("pause");
}

解决方案二：

#include <stdio.h>
void fuzhi(char word1[],char word2[]){
    int i = 0;
    for(i = 0; word2[i] != ''; i++){
        word1[i] = word2[i];
    }
    word1[i] = '';
    puts(word1);
}
void main(){
    char str1[10], str2[10];
    gets(str1);
    gets(str2);
    fuzhi(str1,str2);
    puts(str1);
}