问题描述

java后台如何解析这样的json串？jsonObject和JsonArray不好用，有别的方式吗

[{"_sortNum":0,"_photoId":"2402 ","_updateTime":"2015-12-11 14:55:32","_updateUserName":" ","_ynRelease":1},
{"_sortNum":1,"_photoId":" 2222 ","_updateTime":" 22:22:22 ","_updateUserName":" 张2222 ","_ynRelease":1},
{"_sortNum":2,"_photoId":" 3333 ","_updateTime":" 33:33:33 ","_updateUserName":" 张3333 ","_ynRelease":1},
{"_sortNum":3,"_photoId":" 4444 ","_updateTime":" 44:44:44 ","_updateUserName":" 张4444 ","_ynRelease":1},
{"_sortNum":4,"_photoId":" 5555 ","_updateTime":" 55:55:55 ","_updateUserName":" 张5555 ","_ynRelease":1},{"_sortNum":5,"_photoId":" 6666 ","_updateTime":" 66:66:66 ","_updateUserName":" 张6666 ","_ynRelease":1},{"_sortNum":6,"_photoId":" 7777 ","_updateTime":" 77:77:77 ","_updateUserName":" 张7777 ","_ynRelease":1},{"_sortNum":7,"_photoId":" 8888 ","_updateTime":" 88:88:88 ","_updateUserName":" 张8888 ","_ynRelease":1},{"_sortNum":8,"_photoId":" 9999 ","_updateTime":" 99:99:99 ","_updateUserName":" 张9999 ","_ynRelease":1}]

解决方案

这个格式就是Array的格式,就是需要用JSONArray解析的，检查下是不是你的代码有什么不妥的地方呢？

解决方案二：

创建对象的方法可以试试；或者用map也可以。
public static void ParseJson(String jsonString) {

    // 以employee为例解析，map类似
    JSONObject jb = JSONObject.fromObject(jsonString);
    JSONArray ja = jb.getJSONArray("user");
    List<Offers> userList = new ArrayList<Offers>();
    // 循环添加User对象（可能有多个）
    for (int i = 0; i < ja.size(); i++) {
        Offers user = new Offers();
        user.setName(ja.getJSONObject(i).getString("name"));
        user.setSex(ja.getJSONObject(i).getString("sex"));
        user.setAge(ja.getJSONObject(i).getInt("age"));
        userList.add(user);
    }
    System.out.println("n将Json数据转换为User对象：");
    for (int i = 0; i < userList.size(); i++) {
        Offers user = userList.get(i);
        System.out.println("age: " + user.getAge() + "nname: "
                + user.getName() + "nsex: " + user.getSex());
    }    

    // map:
    JSONArray JMap = jb.getJSONArray("map");

    List<Map<String, Object>> mapList = new ArrayList<Map<String,Object>>();
    Map<String, Object> maps = null;

    for (int i = 0; i < JMap.size(); i++) {
        maps = new HashMap<String, Object>();

        maps.put("name", JMap.getJSONObject(i).get("name"));
        maps.put("sex", JMap.getJSONObject(i).get("sex"));
        maps.put("age", JMap.getJSONObject(i).get("age"));

        mapList.add(maps);
    }

    System.out.println("n将Json数据转换为Map类型");
    for (int i = 0; i < mapList.size(); i++) {
        Map<String, Object> map = mapList.get(i);
        System.out.println("age: " + map.get("age") + "nname: "
                + map.get("name") + "nsex: " + map.get("sex"));
    }
}

解决方案三：

用Gson试试，，，再不行的话，，直接用实体类封装就行了

解决方案四：

先转化成 jsonArray ,再遍历 jsonArray, 通过jsonObject获取信息