问题描述

循环到第二次时scanf函数会自动获取n，这个是为什么？

#include;
//#include
//#define PI 3.1415926
int main(void)
{
char letter=0;
while(1)
{
printf("Enter an upcase letter:");
scanf("%c",&letter);
if(letter>='A')
if(letter<='Z')
{
letter=letter-'A'+'a';
printf("You entered an uppercase %cn",letter);
}
else
printf("Try using the shift key,Bud!I want a capital letter.n");
else
printf("You didn't enter an uppercase letter.n");

};
return 0;

};

解决方案

看 MSDN 的示例，应该不存在所描述的问题。难道是回车多按了一次？

 /* SCANF.C: This program uses the scanf and wscanf functions
  * to read formatted input.
  */

#include <stdio.h>

void main( void )
{
   int   i, result;
   float fp;
   char  c, s[81];
   wchar_t wc, ws[81];

   printf( "nnEnter an int, a float, two chars and two stringsn");

   result = scanf( "%d %f %c %C %s %S", &i, &fp, &c, &wc, s, ws );
   printf( "nThe number of fields input is %dn", result );
   printf( "The contents are: %d %f %c %C %s %Sn", i, fp, c, wc, s, ws);

   wprintf( L"nnEnter an int, a float, two chars and two stringsn");

   result = wscanf( L"%d %f %hc %lc %S %ls", &i, &fp, &c, &wc, s, ws );
   wprintf( L"nThe number of fields input is %dn", result );
   wprintf( L"The contents are: %d %f %C %c %hs %sn", i, fp, c, wc, s, ws);
}
Output
Enter an int, a float, two chars and two strings
71
98.6
h
z
Byte characters

The number of fields input is 6
The contents are: 71 98.599998 h z Byte characters

Enter an int, a float, two chars and two strings
36
92.3
y
n
Wide characters

The number of fields input is 6
The contents are: 456 92.300003 y n Wide characters

解决方案二：

全部输入打印出来对比一下

解决方案三：

好多人都会遇到这问题，因为scanf没读完所有缓存中的信息。把回车剩外面了，被下次的scanf接收到了。