问题描述
最近做EXTJS4 的 东西 遇到了问题 想求教 大家：对嵌入对象做了mapping 可是 取不到 请朋友们指点： 后台发送过来的json 数据{"totalRecord":26,"employees":{"id":1,"dept":{"name":"咨询部",id":3,"description":null,"code":null},"user":null,"title":{"name":"咨询","id":3}}}store:this.store = Ext.create('Ext.data.Store', {fields: ['id',{name:'deptName',mapping:'dept.name'}, {name:'titleName',mapping:'title.name'}, ], pageSize:20, proxy: { type: 'ajax', actionMethods : 'post', url : "aa/aaa", timeout : 1000*60*3, reader: { totalProperty:'totalRecord', type: 'json', root: 'employees', remoteSort: true } } }); grid 中的对应列 this.columns =[{xtype: 'rownumberer',width: 50, sortable: false,align:'center'},{header: '部门', dataIndex: 'deptName',width:150},{header: '职位', dataIndex: 'titleName',width:150} ],fireBug 报出的错误obj.dept is null请问 这个 store 的 fields 应该怎么写？ 请问 这个 store 的 fields 应该怎么写？
解决方案
<script type="text/javascript">Ext.onReady(function(){//创建表格数据var datas = {"totalRecord":26,"employees":{ "id":1, "dept":{"name":"咨询部","id":3,"description":null,"code":null}, //你的数据id前面少了“"user":null, "title":{"name":"咨询","id":3} } };//创建Grid表格组件Ext.create('Ext.grid.Panel',{title : '简单Grid表格示例',renderTo: Ext.getBody(),width:200,height:130,frame:true,viewConfig: {forceFit : true, stripeRows: true//在表格中显示斑马线 },store: {//配置数据源 fields: [{name:'id',mapping:'id'},{name:'deptName',mapping:'dept.name'}, {name:'titleName',mapping:'title.name'}], proxy: { type: 'memory',//Ext.data.proxy.Memory内存代理 data : datas,//读取内嵌数据 reader: { totalProperty:'totalRecord', type: 'json', root: 'employees' } }, autoLoad: true//自动加载 },columns: [//配置表格列{header: "id", width: 30, dataIndex: 'id', sortable: true},{header: "部门", width: 80, dataIndex: 'deptName', sortable: true},{header: "职位", width: 80, dataIndex: 'titleName', sortable: true}]});}); </script>上面为本地测试代码 数据显示成功了 呵呵