问题描述
jqgrid subGridRowExpanded出来的子表格如何获取选中的行？
解决方案
子表格也是一个jqgrid，你可以像操作主表格一样操作子表格的subGridRowExpanded: function(subgrid_id, row_id) {// we pass two parameters// subgrid_id is a id of the div tag created whitin a table data// the id of this elemenet is a combination of the "sg_" + id of the row// the row_id is the id of the row// If we wan to pass additinal parameters to the url we can use// a method getRowData(row_id) - which returns associative array in type name-value// here we can easy construct the flowingvar subgrid_table_id, pager_id;subgrid_table_id = subgrid_id+"_t";pager_id = "p_"+subgrid_table_id;$("#"+subgrid_id).html("<table id='"+subgrid_table_id+"' class='scroll'></table><div id='"+pager_id+"' class='scroll'></div>");jQuery("#"+subgrid_table_id).jqGrid({url:"subgrid.php?q=2&id="+row_id,datatype: "xml",colNames: ['No','Item','Qty','Unit','Line Total'],colModel: [{name:"num",index:"num",width:80,key:true},{name:"item",index:"item",width:130},{name:"qty",index:"qty",width:70,align:"right"},{name:"unit",index:"unit",width:70,align:"right"},{name:"total",index:"total",width:70,align:"right",sortable:false}], rowNum:20, pager: pager_id, sortname: 'num', sortorder: "asc", height: '100%'});jQuery("#"+subgrid_table_id).jqGrid('navGrid',"#"+pager_id,{edit:false,add:false,del:false})},然后子表格的操作就是jQuery("#"+subgrid_table_id).jqGrid('getGridParam','selarrrow');