Given a nested list of integers, implement an iterator to flatten it.
Each element is either an integer, or a list – whose elements may also be integers or other lists.
Example 1:
Given the list [[1,1],2,[1,1]]
,
By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,1,2,1,1]
.
Example 2:
Given the list [1,[4,[6]]]
,
By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,4,6]
.
解题思路
首先递归把integer元素集中到一个list中,然后再借助list的迭代器进行遍历。
实现代码
// Runtime: 6 ms
/**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* public interface NestedInteger {
*
* // @return true if this NestedInteger holds a single integer, rather than a nested list.
* public boolean isInteger();
*
* // @return the single integer that this NestedInteger holds, if it holds a single integer
* // Return null if this NestedInteger holds a nested list
* public Integer getInteger();
*
* // @return the nested list that this NestedInteger holds, if it holds a nested list
* // Return null if this NestedInteger holds a single integer
* public List<NestedInteger> getList();
* }
*/
public class NestedIterator implements Iterator<Integer> {
private List<Integer> nums = new ArrayList<>();
private Iterator<Integer> iterator = null;
public NestedIterator(List<NestedInteger> nestedList) {
for (NestedInteger nestedInteger : nestedList) {
addNestedInteger(nestedInteger);
}
iterator = nums.iterator();
}
@Override
public Integer next() {
return iterator.next();
}
@Override
public boolean hasNext() {
return iterator.hasNext();
}
private void addNestedInteger(NestedInteger nestedInteger) {
if (nestedInteger.isInteger()) {
nums.add(nestedInteger.getInteger());
} else {
List<NestedInteger> nestedList = nestedInteger.getList();
for (NestedInteger nested : nestedList) {
addNestedInteger(nested);
}
}
}
}
/**
* Your NestedIterator object will be instantiated and called as such:
* NestedIterator i = new NestedIterator(nestedList);
* while (i.hasNext()) v[f()] = i.next();
*/
时间: 2024-11-01 15:27:04