问题描述

Android SQLite查询报错

在运行查询语句时，报错语法错误：

inal Cursor c = getContentResolver().query(Provider.GAME_URI new String[]{""CASE WHEN "" +DBHelper.COLUMN_CRE_USER + "" = "" + preferences.getInt(LoginScreen.ID 0) + "" THEN ("" + DBHelper.COLUMN_CRE_PTS + "" AS you AND "" + DBHelper.COLUMN_CON_PTS + "" AS them) ELSE ("" + DBHelper.COLUMN_CON_PTS + "" AS you AND "" + DBHelper.COLUMN_CRE_PTS + "" AS them)""}turn = ?""new String[] { preferences.getInt(LoginScreen.ID 0) + """"} null);

报的错：

04-24 19:57:48.345: E/AndroidRuntime(18775): Caused by: android.database.sqlite.SQLiteException: near ""AS"": syntax error (code 1):  while compiling: SELECT CASE WHEN createduser = 112 THEN (createdplayerpts AS you AND connectedplayerpts AS them) ELSE (connectedplayerpts AS you AND createdplayerpts AS them) FROM game WHERE (turn = ?)

解决方案

类似这种SQL语法错误可以把你的语句先放到sql工具中执行下，首先确保sql语句本身没错，再检查你的代码有没有笔误，类似缺少逗号，括号不匹配这些。

解决方案二：

SELECT     CASE WHEN createduser = 112 THEN createdplayerpts ELSE connectedplayerpts END AS you    CASE WHEN createduser = 112 THEN connectedplayerpts ELSE createdplayerpts END AS themFROM     game WHERE (turn = ?)