问题描述
- 为什么运行后打印的树上没有节点,而且下面也没有编码
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#include<iostream> #include<cstdio> #include<cstring> using namespace std; #define N 10 // 带编码字符的个数,即树中叶结点的最大个数 #define M (2*N-1) // 树中总的结点数目 class HTNode{ // 树中结点的结构 public: char data; int weight; int parent,lchild,rchild; }; class HTCode{ public: char data; // 待编码的字符 int weight; // 字符的权值 char code[N]; // 字符的编码 }; void Init(HTCode hc[], int *n){ // 初始化,读入待编码字符的个数n,从键盘输入n个字符和n个权值 int i; cout<<"输入字符个数:"; cin>>*n; cout<<"输入"<<*n<<"个字符"; fflush(stdin); for(i=1; i<=*n; ++i) cin>>hc[i].data; cout<<"输入"<<*n<<"个权值"; for(i=1; i<=*n; ++i) cin>>hc[i].weight; fflush(stdin); }// void Select(HTNode ht[], int k, int *s1, int *s2){ // ht[1...k]中选择parent为0,并且weight最小的两个结点,其序号由指针变量s1,s2指示 int i; for(i=1; i<=k && ht[i].parent != 0; i++){ ; ; } *s1 = i; for(i=1; i<=k; ++i){ if(ht[i].parent==0 && ht[i].weight<ht[*s1].weight) *s1 = i; } for(i=1; i<=k; i++){ if(ht[i].parent==0 && i!=*s1) break; } *s2 = i; for(i=1; i<=k; i++){ if(ht[i].parent==0 && i!=*s1 && ht[i].weight<ht[*s2].weight) *s2 = i; } } void dayin(HTNode ht[],int k ,int n) { if(k==0) { return; } for (int i=0;i<n;i++) { cout<<" "; } if(ht[k].parent!=0) { cout<<"|_"; } else { cout<<" "; } cout<<ht[k].data<<endl; int L=ht[k].lchild; int R=ht[k].rchild; dayin(ht,R,n+2); dayin(ht,L,n+2); } void HuffmanCoding(HTNode ht[],HTCode hc[],int n){ // 构造Huffman树ht,并求出n个字符的编码 char cd[N]; int i,j,m,c,f,s1,s2,start; m = 2*n-1; for(i=1; i<=m; i++){ if(i <= n) ht[i].weight = hc[i].weight; else ht[i].parent = 0; ht[i].parent = ht[i].lchild = ht[i].rchild = 0; } for(i=n+1; i<=m; i++){ Select(ht, i-1, &s1, &s2); ht[s1].parent = i; ht[s2].parent = i; ht[i].lchild = s1; ht[i].rchild = s2; ht[i].weight = ht[s1].weight+ht[s2].weight; } cd[n-1] = ''; for(i=1; i<=n; i++){ start = n-1; for(c=i,f=ht[i].parent; f; c=f,f=ht[f].parent){ if(ht[f].lchild == c) cd[--start] = '0'; else cd[--start] = '1'; } strcpy(hc[i].code, &cd[start]); } dayin(ht, 2*n-1, 0); } int main() { int i,m,n,w[N+1]; HTNode ht[M+1]; HTCode hc[N+1]; Init(hc, &n); // 初始化 HuffmanCoding(ht,hc,n); // 构造Huffman树,并形成字符的编码 for(i=1; i<=n; ++i) cout<<hc[i].data<<"---"<<hc[i].weight<<endl; //dayin(ht, 2*n-1, 0); return 0; }
时间: 2024-09-28 21:00:12